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algol13
3 years ago
15

A tank in the shape of a right rectangular prism has a height of 5 feet, width of 3 feet, and length of 2 feet. It is full of a

liquid weighing 50 pounds per cubic foot. How much work does it take to pump all of the liquid out of the top of the tank

Mathematics
1 answer:
sveta [45]3 years ago
3 0

Answer:

Step-by-step explanation:

Given

height of tank h=5\ ft

Width of tank w=3\ ft

length of tank L=2\ ft

suppose a layer of water at height h of thickness dh from bottom needed to be pump out

So distance moved by this layer to come out of tank is \Delta h=5-h

weight density of water \rho =50\ pounds/ft

Force required to hold this layer up F_s=2\times 3\times \Delta h\times 50=300\Delta h

Work done to remove the water

W=\int_{0}^{5}300\Delta hdh

W=\int_{0}^{5}300\left ( 5-h\right )dh

W=3750\ Pound-ft

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Your formula here is A=pir^2
Plug in the numbers but instead use 22/7 for pi
A=(22/7)(21)^2
A=22/7*441=1386

Answer is 1386 sq inches 

8 0
3 years ago
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alexandr1967 [171]
The most common expressions involving 16 and w are:
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8 0
3 years ago
Which expression is equivalent to log w (x2-6)4
natka813 [3]
Log w (x^2-6)^4

Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4

Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 =  log w + 4 log (x^2-6)

Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
7 0
4 years ago
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What is the solution set of -9x
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Answer:

B. x≥-3

Step-by-step explanation:

To solve this problem, first you have to isolate it one one side of the equation.  

First, multiply -1 from both sides.

(-9x)(-1)≥27(-1)

Solve.

27*-1=-27

9x≥-27

Next, divide by 9 from both sides.

9x/9≥-27/9

Then, solve.

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Therefore, the correct answer is x≥-3.

5 0
3 years ago
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Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n
Nady [450]

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

The maclaurin series for f(x) is defined by the following formula:

f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}--------------(1)

Where f^{i} is the i - th derivative of the function

If f(x) = e^{-6x}, then the formula of the i - th derivative of the function is:

f^{i} =(-6)^{i} .e^{-6x}----------------------(2)

Then,

f^{i}(0) = (-6)^{i}

Lastly, the equation of the trascendental function by Maclaurin series is: f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i}  }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}---------------(3)

Hence,

The equation of f(x) = e^{-6x} by maclaurin series is f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i}  }{i!}.

Find out more information about maclaurin series here

brainly.com/question/24179531

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4 0
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