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ELEN [110]
3 years ago
10

When rounded, what is the value of the 6 in 4.769

Mathematics
1 answer:
levacccp [35]3 years ago
7 0
If u round tha to the nearest 10th it’s 4.8
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Madison has set up a lemonade stand outside her house and sells small cups and large cups of lemonade. Each small cup holds 12 o
Troyanec [42]

Answer:

12x+22(y+10)=1240, y=x

small cups=30

large cups=40

Step-by-step explanation:

let x be the number of small cups and y the number of large cups.

-Given that 10 more cups than small cups of lemonade were sold:

12x+22(y+10)=1240

#Before the 10 more were sold, the number of x and y sold were equal>

x=y\\\\\therefore 12x+22(x+10)=1240\\\\12x+22x+220=1240\\\\34x=1240-220\\\\34x=1020\\\\x=30

The number of small cups sold was 30

#Since, the number of large cups was 10 more, y=x+10=30+10=40

7 0
3 years ago
Read 2 more answers
Daneielle's rectangular bedroom has an area of 12 3/4 square meters.It is 3.4 meters long. How many meters wide is Danielle's be
ExtremeBDS [4]
12 3/4 as a decimal is 12.75
The area of a rectangle is length times width.
So if you divide the area (12.75) by the length(3.4)
you will get a width (and answer) of 3.75 :)

7 0
3 years ago
3(2+q)+153(2+q)+15 simplified is
blondinia [14]
6 + 3q + 306 + 153q + 15
156q + 327
8 0
3 years ago
Which of the following is a polynomial?
Zanzabum

Answer:

I'm pretty sure A is the correct answer :)

(x-2)(x^4+3) is a polynomial

5 0
2 years ago
You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop
Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

P(A) = 0.99*0.1 + 0.9*0.9 = 0.909

What is the probability that this person has the flu?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11

The correct answer is:

E. 0.11

5 0
3 years ago
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