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yan [13]
3 years ago
9

I need someone to help me solve this problem 7/b+5=10/5

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
5 0
I think the answer is 7/3
ch4aika [34]3 years ago
4 0
7/b + 5 = 10/5
7/b + 5 = 2
7/b = 2 - 5
7/b = -3
-3b = 7
b = 7/-3
b = -7/3.

This would be the solution to the question.
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The isosceles triangle has two sides with the same length. The base is one-half the length of a side. The expression which repre
gavmur [86]

Answer:

20 units

Step-by-step explanation:

s = 8

Perimeter = s + s + \frac{1}{2}*s

                = 8 + 8 + \frac{1}{2}*8

                = 8 + 8 + 4

               = 20 units

8 0
3 years ago
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A teacher wants to know whether the boys in the entire school prefer watching television or playing outdoor games after school.
sweet-ann [11.9K]
Hello!

You want a choice where everyone has an equal chance to answer

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7 0
3 years ago
Find the solution set for this inequality:
Zepler [3.9K]
Answer is c I believe, so sorry if I’m wrong
5 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
A jar contains 38 red marbles numbered 1 to 38 and 38 blue marbles numbered 1 to 38 a marble is drawn at random from the jar
liq [111]

Answer:

P(Red) = 0.50'

P(Odd) = 0.50\\

Step-by-step explanation:

Given

Red = 38

Blue = 38

Required (Missing part of the question)

(a) The marble is red. (b) The marble is odd-numbered

Solving (a): Probability of Red.

This is calculated as:

P(Red) = \frac{Red}{Total}

P(Red) = \frac{38}{38+38}

P(Red) = \frac{38}{76}

P(Red) = 0.50

Solving (b): Probability of Odd

Since each marble type is numbered 1 to 38, then half of it are odd.

i.e. 19 odd numbered red marbles and 19 odd numbered blue marbles.

So, the probability of odd is:

P(Odd) = \frac{Odd}{Total}

P(Odd) = \frac{19+19}{38+38}

P(Odd) = \frac{38}{76}

P(Odd) = 0.50\\

5 0
3 years ago
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