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2 years ago

A town has a population of 13000 and grows at 2.5% every year. What will be the

Mathematics

1 answer:

amid [387]2 years ago

8 0

Answer:

14708

Step-by-step explanation:

The growth factor is 100% + 2.5% = 102.5% = 1.025

Population after 5 years

= 13000 × $(1.025)^{5}$

≈ 14708 ( to the nearest whole number )

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Is it possible for the line segments of a triangle to be 6 cm, 7 cm, and 12 cm in length?

Paul [167]

Answer:

Yes because sum of 2 line segment is greater than the third side

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What addition doubles fact can help you find 4+3

PtichkaEL [24]

The answer would be 7

8 0

2 years ago

I don’t know what the answer to this question is , help

ipn [44]

Answer:

(4, 0)

Step-by-step explanation:

given the 2 equations

y = x - 4 → (1)

- 4x - 6y = - 16 → (2)

substitute y = x - 4 into (2)

- 4x - 6(x - 4) = - 16

- 4x - 6x + 24 = - 16

- 10x + 24 = - 16 ( subtract 24 from both sides )

- 10x = - 40 ( divide both sides by - 10 )

x = 4

substitute x = 4 into (1) for corresponding value of y

y = 4 - 4 = 0

solution is (4, 0)

3 0

2 years ago

I need the answer and the work please !!!

algol [13]

2a.) 8.8 x 4 = 35.2g
2b.) 35.2 x 30 = 1056g or 1.056kg

6 0

3 years ago

The perimeter of a rectangular baking sheet is 58 inches and its area is 201.25 in.2. What are the length and width of the bakin

anzhelika [568]

Answer:

$Length=17.5\ in\\\\Width=11.5\ in$

Step-by-step explanation:

The formula for calculate the Area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

And the formula for calculate the peimeter of a rectangle is:

$P=2l+2w$

Where "l" is the lenght and "w" is the width.

We know that the perimeter of the rectangular baking sheet is 58 inches and its area is 201.25 in². Then:

$A=201.25\ in^2\\\\P=58\ in$

<u>The steps are:</u>

1. Solve for the "l" from the formula $A=lw$ :

$A=lw\\\\l=\frac{A}{w}\\\\\l=\frac{201.25}{w}$

2. Substitute $l=\frac{201.25}{w}$ into the formula $P=2l+2w$ and solve for "w":

$58=2(\frac{201.25}{w})+2w\\\\58=\frac{402.5}{w}+2w\\\\58=\frac{402.5+2w^2}{w}\\\\58w=402.5+2w^2\\\\2w^2-58w+402.5=0$

Applying the Quadratic formula $x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$ , we get:

$x=w=\frac{-(-58)\±\sqrt{(-58)^2-4(2)(402.5)}}{2(2)}\\\\w_1=17.5\\\\w_2=11.5$

3. Substitute $w_1=17.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{17.5}=11.5$

4. Substitute $w_2=11.5$ into $l=\frac{201.25}{w}$ :

$l=\frac{201.25}{11.5}=17.5$

Therefore, since the value of the lenght of a rectangle must be greater that the value of the width, we can conclude that the lenght and the width of the rectangular baking sheet are:

$l=17.5\ in\\\\w=11.5\ in$

8 0

3 years ago