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2 years ago

Why does 20x700=14000 please give details

Mathematics

1 answer:

Butoxors [25]2 years ago

8 0

Answer:

When multiplying zeros, you first remove the zeros.

So,

2 x 7 = 14

Then you add the zeros to the answer.

We had three zeros

So we add three zeros to 14

14,000

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How do I solve the equation in an interval from 0 to 2π ? 9 cos 2t = 6

Ivahew [28]

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Using the fact that cos is 2π-periodic, we have

$\cos(2t)=\dfrac23\implies2t=\cos^{-1}\left(\dfrac23\right)+2n\pi$

That is, $\cos(\theta+2n\pi)=\cos\theta$ for any $\theta$ and integer $n$ .

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We get 2 solutions in the interval [0, 2π] for $n=0$ and $n=1$ ,

$t=\dfrac12\cos^{-1}\left(\dfrac23\right)\text{ and }t=\dfrac12\cos^{-1}\left(\dfrac23\right)+\pi$

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2 years ago

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Answer:

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3 years ago

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creativ13 [48]

2 is the slope so the slope perpendicular to that is -1/2 (negative reciprocal)
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2 years ago

Design a sine function with the given properties:

Rom4ik [11]

Answer:

$f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$ .

Step-by-step explanation:

Given information:

Period = 24 hr

Maximum = 16 at t=16 hr.

Minimum = 10 at t=4 hr.

The general sin function is

$y=A+\sin(B(x-C))+D$ .... (1)

where, |A| is altitude, $\frac{2\pi}{B}$ is period, C is phase shift and D is midline.

Period is 24 hr.

$24=\dfrac{2\pi}{B}\Rightarrow B=\dfrac{\pi}{12}$

Altitude is

$A=\dfrac{Maximum-Minimum}{2}=\dfrac{16-10}{2}=3$

$D=\dfrac{Maximum+Minimum}{2}=\dfrac{16+10}{2}=13$

The function is minimum at t=4 and maximum at t=16,phase shift is

$C=\dfrac{16+4}{2}=10$

Substitute these values in equation (1).

$y=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$

Therefore, the required function is $f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$ .

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