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3 years ago

The perimeter of a garden is 82 feet. The length is 5 more than twice the width. What is the width of the garden?

Mathematics

2 answers:

Ivahew [28]3 years ago

5 0

Answer:

it is 16

Step-by-step explanation:

because you dont multiply 5 times sixteen ugh idk................................

Morgarella [4.7K]3 years ago

4 0

Answer:

The width of the garden is 12 feet

Step-by-step explanation:

1) 82ft = 2(2W + 5 + W)

Divide each side by 2:

2) 41ft = 3W + 5

Subtract 5 from each side:

3 )36ft = 3W

Divide each side by 3:

4) 12ft = W

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A business could not collect $5,000 that it was owed. The total owed to the business was $100,000. What fraction of the total wa

son4ous [18]

Total owed to the business = $100,000

amount that could not be collected = $5000

Fraction of total not collected

$\text{fraction not collected=}\frac{5000}{100000}=\frac{5}{100}=\frac{1}{20}$

3 0

1 year ago

what is the distance between the points (23,-33) and (4,9) if necessary round your answer to two decimal places

Rufina [12.5K]

The distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.

<h3>What is the distance between the points (23,-33) and (4,9)?</h3>

The distance between two points on a graph can be determined using the equation;

D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]

Given that;

x₁ = 23
x₂ = 4
y₁ = -33
y₂ = 9

We substitute our values into the equation above.

D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]

D = √[ ( 4 - 23 )² + ( 9 - (-33) )² ]

D = √[ ( -19 )² + ( 42 )² ]

D = √[ 361 + 1764 ]

D = √[ 2125 ]

D = 46.10

Therefore, the distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.

Learn more about distance formula here: brainly.com/question/7592016

#SPJ1

7 0

2 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

2 years ago

HELP ASAP I HATE MATH

Arte-miy333 [17]

Answer:

step attached

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What's the greatest common factor of 8, 44, and 12

lubasha [3.4K]

Answer:

Step-by-step explanation:

the greatest common factor of 8,44,12 is 4

8 0

3 years ago