Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.

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Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as
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by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
Answer:
Step-by-step explanation:
We have three people
jamal = x (since im guessing hes the youngest)
wesley= x+1
John= x+2
the formula you would use is x+x+1+x+2=108
when you simplify that you get 3X+3=108
you subtract the 3 from 108 which leaves you with 3X=105
divide that by 3 which makes x=35
so
jamal is 35
wesley is 36
john is 37
No it is not a function, because a function cannot have more than one output per input. When x=-3, there are two solutions shown: (-3,2) and (-3,3), therefore it cannot be a function.