If you multiply 38.95 by 0.02, you will get the amount taken away from the total when the discount is applied:38.95x0.02=0.78
Then, you subtract that discount price from the total to get the amount Joan pays when she pays with cash:38.95-0.78=38.17
Joan pays $38.17 in cash.
You would round 1.049 to 1.05.
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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It's in expanded form, so you add each part (thousands, hundreds, tens, and ones) separately. the hundreds is missing. looking at the number, it is 900.
Answer:
x = 5
Step-by-step explanation:
Add the degrees of m<VUJ and m<JUT and make them equal to 175 since both angles exist with m<VUT.
17x - 3 + 17x + 8 = 175
34x - 3 + 8 = 175
34x + 5 = 175
34x = 170
x = 5