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Serggg [28]
3 years ago
9

Given that ​f(x) = x + 4 and ​g(x)​ = x^{2} - x, find ​(f​ + g)(​5), if it exists.

Mathematics
2 answers:
nordsb [41]3 years ago
4 0
Uaihwyeurvgeiiscsbakatfrvd
user100 [1]3 years ago
3 0

Answer:

4

Step-by-step explanation:

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For Question 1 the answer is the last choice.
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ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

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3 years ago
How do write a word problem for the following equation:
lozanna [386]
Three and a half divided by seven-eighth equals seven over two times eight over seven equals fifty over fourteen equals four
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Please show your work. The data modeled by the box plots represents the battery life of two different brand of batteries that Ji
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(a) Brand X median  = 13
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During a flu epidemic a company with 200 employees had 1/3 on Monday and another 3/10 call in sick on Tuesday.
valkas [14]

<u>Part</u><u> </u><u>(</u><u>a</u><u>)</u>

\frac{1}{10}+\frac{3}{10}=\frac{4}{10}=\boxed{\frac{2}{5}}

<u>Part</u><u> </u><u>(</u><u>b</u><u>)</u>

200\left(\frac{2}{5} \right)=\boxed{80}

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2 years ago
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