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Sergeeva-Olga [200]

3 years ago

12

The fourth grade students are running a food drive. They want to collect 1000 cans of food. They need to collect 8 times and man

y cans as they already have in order to reach their goal. How many cans do they already have?

1 answer:

EleoNora [17]3 years ago

8 0

They already have 125

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Triangle ABC is similar to triangle DEF. how long is EF?<br> A) 4<br> B) 10<br> C) 14<br> D) 12

Andrej [43]

Answer:

The answer is D) 12

Step-by-step explanation:

Multiple 4 by 3

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3 years ago

A carton of eggs costs $2.90 and a package of bacon costs $3.10. How much

Dominik [7]

Answer:

$8.90

Step-by-step explanation:

((2)(2.90))+(3.10)= $8.90

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Hayden is a manager at a landscaping company. He has two workers to landscape an entire park, Cody and Kaitlyn. Cody can complet

belka [17]

Answer: 3.4 h

Explanation:

1) The basis to solve this kind of problems is that the speed of working together is equal to the sum of the individual speeds.

This is: speed of doing the project together = speed of Cody working alone + speed of Kaitlyin working alone.

2) Speed of Cody

Cody can complete the project in 8 hours => 1 project / 8 h

3) Speed of Kaitlyn

Kaitlyn can complete the project in 6 houres => 1 project / 6 h

4) Speed working together:

1 / 8 + 1 / 6 = [6 + 8] / (6*8 = 14 / 48 = 7 / 24

7/24 is the velocity or working together meaning that they can complete 7 projects in 24 hours.

Then, the time to complete the entire project is the inverse: 24 hours / 7 projects ≈ 3.4 hours / project.Meaning 3.4 hours to complete the project.

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3 years ago

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When 12 is added to a number the result is 32 less than 3 times the number.

sdas [7]

Let the number = x

12 + x = 3x - 32

x = 3x - 44 Subtract 12 from both sides

-2x = -44 Subtract 3x from both sides

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What is the greatest common factor of 44c^5, 22c^3 and 11c^4

Alexxandr [17]

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of $44c^5, 22c^3 , 11c^4$

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

$\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}$

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

$\text{ Step 2: GCF of }c^5, c^3 , c^4$

$c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1$

Thus the greatest common factor is $c^3$

Step 3: Multiply the GCF of 44, 22, 11 and GCF of $c^5, c^3 , c^4$

$\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3$

Thus $\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3$

8 0

3 years ago