2 years ago

What is the area of a rectangle if the length is 12 cm and the width is 7 cm?

Mathematics

2 answers:

Zepler [3.9K]2 years ago

8 0

Answer:

Step-by-step explanation:

you would multiply the length versus the width

frozen [14]2 years ago

8 0

Answer:

12×7==========N

Step-by-step explanation:

12×7=84, cause the formula of looking for the area is A=L×W

You might be interested in

Subtract 7xy (x² - 2xy + 3y²) - 8x (x²y - 4xy + 7x y2) from 3y(4x²y-5xy +8xy²)

olganol [36]

Answer:

im not sure but

Step-by-step explanation:

5 0

3 years ago

PLLLEASEEE HELLPPP I WILL GIVE BRAINLIEST!!!!

vesna_86 [32]

Answer:

Step-by-step explanation:

to make it quick

2*110 = arc FI

220° = arc FI

arc LI = 97°

arc FL = x

360 = 220 + 97 + x

43 = X

arc FL = 43°

4 0

3 years ago

Divide. Show your work. (6x^4-5x^3+6x^2)/2x^2

serg [7]

We can do like we did before, distribute the denominator,

$\bf \cfrac{6x^4-5x^3+6x^2}{2x^2}\implies \cfrac{6x^4}{2x^2}-\cfrac{5x^3}{2x^2}+\cfrac{6x^2}{2x^2}\implies \cfrac{6}{2}\cdot \cfrac{x^4}{x^2}-\cfrac{5}{2}\cdot \cfrac{x^3}{x^2}+\cfrac{6}{2}\cdot \cfrac{x^2}{x^2}
\\\\\\
3 x^4x^{-2}-\cfrac{5}{2}x^3x^{-2}+3x^2x^{-2}\implies 3x^{4-2}-\cfrac{5}{2}x^{3-2}+3x^{2-2}
\\\\\\
3x^2-\cfrac{5}{2}x+3x^0\implies 3x^2-\cfrac{5}{2}x+3$

6 0

3 years ago

Please help me solve this

Thepotemich [5.8K]

Answer:

t=3.2c

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help with this question

myrzilka [38]