Set up the following equations:


110 represents the lengths of the length and width of the triangle, as you'll divide total perimeter of the rectangle, 220, by 2 to find the individual lengths. 20 is the difference between the length and width.
We'll use elimination for this system of equations, as there are opposite coefficients for W in both equations. Combine the two equations:

Divide both sides by 2 to get L by itself:
The length of the rectangle is 65 feet.Plug this value into the second equation:

Add W to both sides:

Subtract 20 from both sides:
The width of the rectangle is 45 feet.
<h3>
Answer: 40</h3>
=================================================
Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
--------------
We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.
I’m think the answer is 28
Please edit your question to what is the question