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vaieri [72.5K]
3 years ago
11

A car that normally sells for $20,000 is on sale for $16,000. The sales tax is 7.5% What percent of the original price of the ca

r is the final price?
Show your work to solve this problem.
Mathematics
2 answers:
erastova [34]3 years ago
7 0

Answer:

80

Step-by-step explanation:

Aleonysh [2.5K]3 years ago
4 0
The answer will be 80
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RATES AND RATIOS
docker41 [41]
Blue to orange
6 : 5
24 : x

24 \div 6 = 4 \\ 5 \times 4 = 20

There are 20 orange M&M's.

Hope this helps. - M
6 0
3 years ago
Help 0.06 is 10 times as much as
Ipatiy [6.2K]

Answer:

0.06 is 10 times as much as 0.006

Step-by-step explanation:

let the number be x

as per the condition 0.06 is 10 times as much as x.

Solve for x:

10 times as much as x represents as 10 \times x

Then;

0.06 = 10 \times x                 ......[1]

Division property of equality states that you divide the same number to both sides of an equation.

divide by 10 to both sides in equation [1];

\frac{0.06}{10} = \frac{10x}{x}

Simplify:

x = 0.006

Therefore, 0.06 is 10 times as much as 0.006


3 0
3 years ago
Read 2 more answers
Please help me out with this!!!!!!!!!!!!
vesna_86 [32]

Answer:

y = - \frac{3}{4} x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2points on the line

m = \frac{0-3}{4-0} = - \frac{3}{4}

Note the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = - \frac{3}{4} x + 3 ← equation of line

6 0
3 years ago
A triangle has a perimeter of 51 cm. If the three sides of the triangle are n, 4n-4, and 4n-8, what is the length of each side?
True [87]

Answer:

see below

Step-by-step explanation:

The three sides add to 51

n      +    4n-4    +   4n-8   = 51

9n -12 = 51

9n = 63

n = 7        4n-4 = 24      4n-8 = 20  

6 0
2 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
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