Answer:
![9c^3 - 12c^2 - 18c - 24= [3c^2 - 6][3c - 4]](https://tex.z-dn.net/?f=9c%5E3%20-%2012c%5E2%20-%2018c%20-%2024%3D%20%5B3c%5E2%20-%206%5D%5B3c%20-%204%5D)
Step-by-step explanation:
Given

Required
Factor
Group into 2
![[9c^3 - 12c^2] - [18c + 24]](https://tex.z-dn.net/?f=%5B9c%5E3%20-%2012c%5E2%5D%20-%20%5B18c%20%2B%2024%5D)
Factorize each group
![3c^2[3c - 4] - 6[3c - 4]](https://tex.z-dn.net/?f=3c%5E2%5B3c%20-%204%5D%20-%206%5B3c%20-%204%5D)
Factor out 3c - 4
![[3c^2 - 6][3c - 4]](https://tex.z-dn.net/?f=%5B3c%5E2%20-%206%5D%5B3c%20-%204%5D)
Hence:
![9c^3 - 12c^2 - 18c - 24= [3c^2 - 6][3c - 4]](https://tex.z-dn.net/?f=9c%5E3%20-%2012c%5E2%20-%2018c%20-%2024%3D%20%5B3c%5E2%20-%206%5D%5B3c%20-%204%5D)
X+3≤ -5+2x
Add 5 to the other side. (the inverse of subtraction, since 5 is negative)
x+8≤2x
Subtract x on both sides.
8≤x <- the answer
I hope this helps!
~kaikers
its the first 1. b.
Step-by-step explanation:
nb. b. b b b bcbcbc
Answer:
The velocity is 17 m/s
Step-by-step explanation:
To find the velocity, we find the first differential of the displacement
That will be
S’(t) = 16t + 1/t
We simply proceed to replace t with 1
That will give;
16(1) + 1/1
= 16 + 1 = 17 m/s
This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent ' sin(2x) ' .
Here we go:
Original equation: Q² - 0.5 Q = 0
Factor the left side: Q (Q - 0.5) = 0
This equation is true if either factor is zero:
-- If Q=0, then sin(2x) = 0
2x = 0°, 180°, 360°
x = 0°, 90°, 180°
-- If (Q-0.5) = 0, then Q = 0.5
sin(2x) = 0.5
2x = 30°, 150°
x = 15°, 75°
The whole collection of solutions
between 0° and 360° :
x = 0°, 15°, 75°, 90°, 180° .