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vfiekz [6]
3 years ago
5

I have 2 bags of counters. The first bag contains 2 red counters and 1 blue counter. The second bag contains 1 red counter, 1 bl

ue counter and 2 yellow counters. I take a counter at random from both bags, what is the probability that two counters will be the same colour?

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0
3/12, i used a tree diagram to work it out

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What is 3/4 equal too
Dovator [93]
3/4 is equal to .75 .................................
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3 years ago
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If D is the midpoint of CE, CD= 9x-7, and DE= 3x+17, find CE
tatuchka [14]
Hello!

Since D is the midpoint and the two equations are and both sides of point D the equations equal each other

9x - 7 = 3x + 17

Now you solve it algebraically

Add 7 to both sides

9x = 3x + 24

Subtract 3x from both sides

6x = 24

Divide both sides by 6

x = 4

Now we put this into both equations and add them

9(4) - 7 = 29
3(4) + 17 = 29

29 + 29 = 58

The answer is 58 units

Hope this helps!
3 0
3 years ago
Question 12 (1 point) Given P(A) 0.34, P(A and B) 0.27, P(A or B) 0.44, what is P(B)? Answer in decimal form. Round to 2 decimal
Tema [17]

Answer:  The required probability of event B is P(B) = 0.37.

Step-by-step explanation:  For two events A and B, we are given the following probabilities :

P(A) = 0.34,    P(A ∩ B) = 0.27   and   P(A ∪ B) = 0.44.

We are to find the probability of event B, P(B) = ?

From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow 0.44=0.34+P(B)-0.27\\\\\Rightarrow 0.44=0.07+P(B)\\\\\Rightarrow P(B)=0.44-0.07\\\\\Rightarrow P(B)=0.37.

Thus, the required probability of event B is P(B) = 0.37.

6 0
3 years ago
What is the sum of the arithmetic sequence 3, 9, 15…, If there are 34 terms?
snow_tiger [21]

Answer:

first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.

we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)

an = a1 + (n-1) * d

n = the term we want to find = 34

a1 = first term = 3

d = common difference = 6

now we sub

a34 = 3 + (34-1) * 6

a34 = 3 + (33 * 6)

a34 = 3 + 198

a34 = 201

now we use the sum formula

Sn = (n (a1 + an)) / 2

S34 = (34(3 + 201))/2

s34 = (34(204)) / 2

s34 = 6936/2

s34 = 3468 <=== the sum of the first 34 terms:

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3 years ago
What is the caputal of idaho
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Capital of Idaho is boise this is not a math question

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