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Kay [80]
3 years ago
8

Can you please help me simplify equation 10(2+3)-8×3​

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

26

Step-by-step explanation:

10(2+3)-8×3

10×5-24

50-24

26

baherus [9]3 years ago
5 0

Answer:

26

10(2+3)-8×3

10(5)-8×3

50-24 = 26

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Which statement is true about the ordered pair (5 , 2)? A. To plot the ordered pair (5 , 2), travel two units to the right on th
MissTica

Answer:

b

Step-by-step explanation:

you can tell because it cant be D or C because you cant go right on the y axis and up on the x axis. it cant be A because 5 is the x and 2 is the y. A says that 5 is the y and 2 is the x. so it has to be B.

8 0
3 years ago
Help, please <br> Giving you 39 points!!
vova2212 [387]

Answer:

n = 10

Step-by-step explanation:

The triangles are equal by SSS theorem, therefore the 2 angles given with a variable must be equal.

6 0
3 years ago
Determine whether (18 + 35) × 4 = 18 + 35 ×4 is true or false. explain
fomenos
The first one  is 212 
and the second one is 158
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6 0
3 years ago
What is the maximum r-value for the polar equation r = -3 + 5 sin theta? Note that a maximum r-value is a maximum value of (r),
kipiarov [429]

Answer:

+2

Step-by-step explanation:


The given equation, r = -3 + 5 sin theta, includes a sine term whose max value is +5 and whose min value is -5.  We are interested in finding the max value that r can have.  To obtain this, take that constant term, -3, and add teh max value of the sine function, which is +5.  Net:  5 - 3 = 2.

The max value that r = -3 + 5 sin theta can take on is +2.

5 0
3 years ago
Read 2 more answers
39/51 change to lowest terms
OLEGan [10]

Answer:

As a proper fraction  - 39/51 = 13/17

As a decimal number:  39/51 ≈ 0.76

As a percentage:  39/51 ≈ 76.47%

Step-by-step explanation:

Calculate the greatest (highest) common factor (divisor), gcf (gcd).

13/17 =

13 ÷ 17 =

0.764705882353 ≈

0.76

By precentage

0.764705882353 =

0.764705882353 × 100/100 =

76.470588235294/100 =

76.470588235294% ≈

76.47%

7 0
3 years ago
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