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jeka94
3 years ago
8

in ΔABC, ∠ABC is a right angle, AB = 3 units, and BC = 2 units. ΔABC is dilated by a scale factor of 0.5 with point B as the cen

ter of dilation, resulting in the image ΔA′B′C′. Which statement about A′B′ is true?
Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

the first one i think

Step-by-step explanation:

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Find the missing term and the missing coefficient 6a −( )5a =( ) a2 − 35a
andrew11 [14]
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
 Let the missing term be X
 Let the missing coefficient be Y
 Therefore, (6a – X)5a = Y(a^2) – 35a
 6a x 5a – X.5a = Y.a^2 – 35a
 30a^2 – X.5a = Y.a^2 – 35a
  Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
 30 = Y; 5X = 35
Y = 30; X = 7
   Therefore, (6a-7)5a = 30 a^2 – 35a <span>
</span>
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3 years ago
Find the slope of the lines. Are the 2 lines parallel or perpendicular? Explain how you can use the slope of two lines to tell i
rewona [7]

Answer:

slope = \frac{3}{7} and - \frac{7}{3}, perpendicular

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = \frac{3}{7} x + 11 is in this form with m = \frac{3}{7}

Rearrange 7x + 3y = 13 into this form

subtract 7x from both sides

3y = - 7x + 13 ( divide all terms by 3 )

y = - \frac{7}{3} x + \frac{13}{3} ← in slope- intercept form

with m = - \frac{7}{3}

• Parallel lines have equal slopes

• The product of perpendicular slopes = - 1

The lines are not parallel since slopes are not equal

\frac{3}{7} × - \frac{7}{3} = - 1

Hence lines are perpendicular



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What is 7.4 x 10 and what is 7.4 x 100
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74 and 740

Step-by-step explanation:

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