Answer:
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Let 'S' be the sample space associated with the drawing of a card
n (S) = 52C₁ = 52
Let E₁ be the event of the card drawn being a king

Let E₂ be the event of the card drawn being a queen

But E₁ and E₂ are mutually exclusive events
since E₁ U E₂ is the event of drawing a king or a queen
<u><em>step(ii):-</em></u>
The probability of drawing of a king or a queen from a standard deck of playing cards
P( E₁ U E₂ ) = P(E₁) +P(E₂)

P( E₁ U E₂ ) = 
<u><em>step(iii):-</em></u>
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards



<u><em>Conclusion</em></u>:-
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
Answer:
2
Step-by-step explanation:
simplify......dndjddjejdjdjehdeww
This is a fair assumption, but not true in every instance. Since home runs do not indicate how many runs score, which are the decider in a win or a loss, they are less accurate at predicting.
Answer:
Step-by-step explanation:
The answer A on 2021
Hey, don’t call for that link thing. It’s fake. Here’s how I solved this: x = [35(80%) + 70(25%)]/(35 + 70) = 43.3%
The answer is 43.3%