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devlian [24]
3 years ago
6

Perform the indicated operation and simplify the result.

Mathematics
1 answer:
Sonbull [250]3 years ago
4 0

Given:

$\frac{a-a b}{a^{2}} \div \frac{a-1}{a^{3}}

Solution:

$\frac{a-a b}{a^{2}} \div \frac{a-1}{a^{3}}

Apply the fraction rule:

$\frac{w}{x} \div \frac{y}{z}=\frac{w}{x} \times \frac{z}{y}

Using this rule,

$\frac{a-a b}{a^{2}} \div \frac{a-1}{a^{3}}=\frac{a-a b}{a^{2}} \times \frac{a^{3}}{a-1}

Factor out common term a in first fraction.

                       $=\frac{a(1-b)}{a^{2}}\times \frac{a^{3}}{a-1}

Cancel the common factor a.

                        $=\frac{1-b}{a} \times \frac{a^{3}}{a-1}

Apply the multiplication of fraction rule:

$\frac{w}{x} \times \frac{y}{z}=\frac{w \times y}{x \times z}

Using this rule, we get

                         $=\frac{(1-b) a^{3}}{a(a-1)}

Cancel the common factor a.

                         $=\frac{a^{2}(1-b)}{a-1}

Therefore,

$\frac{a-a b}{a^{2}} \div \frac{a-1}{a^{3}}=\frac{a^{2}(1-b)}{a-1}

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Answer:

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Step-by-step explanation:

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In this case the two equations describe lines that intersect at one particular point. Clearly this point is on both lines, and therefore its coordinates (x, y) will satisfy the equation of either line. Thus the pair (x, y) is the one and only solution to the system of equations. One solution is called "consistent". This shows two distinct non-parallel lines that cross at exactly one point. This is called an "independent" system of equations, and the solution is always some x, y-point.  

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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Hope this helped

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