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Citrus2011 [14]
2 years ago
13

Can you guys check if my answer is right please? Will give brainiest to best answer

Mathematics
1 answer:
frutty [35]2 years ago
5 0
≈452.39
A=4•pi•r^2
Hope this is correct! :)
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The Late Show with David Leterman is seen by a relatively large percentage of household members who record the show for viewing
Zanzabum

Answer:

a) Null hypothesis:\mu \leq 40000  

Alternative hypothesis:\mu > 40000  

b) t=\frac{41182-40000}{\frac{19990}{\sqrt{1700}}}=2.438    

c) The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since the sample size is large enough we cna use the z distribution as an approximation for the statsitic on this case.

Since is a one right tailed test the p value would be:  

p_v =P(t_{(1699)}>2.438)=0.0074  

d) If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis at 1% of signficance.  So we can conclude that the true mean is higher than 40000 at the significance level assumed.

Step-by-step explanation:

Data given and notation  

\bar X=41182 represent the sample mean

s=19990 represent the sample standard deviation

n=1700 sample size  

\mu_o =40000 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is greater than 40000, the system of hypothesis would be:  

Null hypothesis:\mu \leq 40000  

Alternative hypothesis:\mu > 40000  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{41182-40000}{\frac{19990}{\sqrt{1700}}}=2.438    

Part c: P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since the sample size is large enough we cna use the z distribution as an approximation for the statsitic on this case.

Since is a one right tailed test the p value would be:  

p_v =P(t_{(1699)}>2.438)=0.0074  

Part d: Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis at 1% of signficance.  So we can conclude that the true mean is higher than 40000 at the significance level assumed.

3 0
3 years ago
Dressed like me walk talk and act like me just might be the next best thing but not quite me
OLEGan [10]

Answer:

Okay..

Step-by-step explanation:

Your are cunfoosing, help meh understand what ur sayin

5 0
3 years ago
What is the y-intercept of the line y + 11 = –2(x + 1.5)? y-intercept =
Lana71 [14]

y + 11 = –2(x + 1.5)

y=mx+b

multiply the bracket by -2

(-2)(x)=-2x

(-2)(1.5)=-3

y+11=-2x-3

move +11 to the other side

sign changes from +11 to -11

y+11-11=-2x-3-11

y=-2x-14

m is also the slope

b= y-intercept

Answer:

y-intercept=-14

6 0
3 years ago
What is 1 1/5 subtracted by 3 1/10<br>whoever gets it right I will choose as the brainliest
pickupchik [31]

Answer:

6/5÷31/10=12/31

Step-by-step explanation:

6/5÷31/10=?Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

6/5×10/31=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

6×10 5×31=60/155

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 60 and 155 using

GCF(60,155) = 5

60÷51   55÷5=12/31

Therefore:

65÷3110=12/31

7 0
3 years ago
WILL MARK BRAINLIEST!!!
Elan Coil [88]

Answer:

b

Step-by-step explanation:

count two up, and 5 to the right

8 0
3 years ago
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