The width of the rectangle is twice the length of the rectangle
<h3>How to compare the dimensions of the rectangle?</h3>
The given parameters are:
Width = 4 cm
Length = 2 cm
Express 4 cm as 2 * 2 cm
Width = 2 * 2 cm
Substitute Length = 2 cm in Width = 2 * 2 cm
Width = 2 * Length
This means that the width of the rectangle is twice the length of the rectangle
Hence, the true statement is that the width of the rectangle is twice the length of the rectangle
Read more about rectangles at:
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Answer:
Step-by-step explanation:idk
Idk
1. You have that a<span> student's pay of $18 an hour </span>is <span>$4 more than twice the amount the student earns per hour at an internship.
2. So, let's call the </span><span>hourly pay of the internship: "x". Then, you have:
</span><span>
18=2x+4
3. When you clear the variable "x", you obtain:
18-4=2x
14=2x
x=14/2
x=$7
Therefore, the answer is: T</span><span>he hourly pay of the internship is $7.</span>
Answer= 70.7 meters.
Step-by-step explanation:
We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.
Since we know that diagonal of a square is product of side length of square and . So we will find diagonal of our given square plaza by multiplying 50 by .
Therefore, diagonal distance across the plaza is 70.7 meters.
So you can you the Pythagorean theorem to solve this problem.
if each side of the square is a certain length x, then the square is made up of two right triangles.
the sides adjacent to the right angle are length x while the hypoteneus is the diagonal whcih measures 36 feet.
a^2 + b^2 = c^2
x^2 + x^2 = 36^2
2x^2 = 1296
x^2 = 648
x = 25.456
area of a square = x^2 = 648 ft^2
