Question

Number 13 pleaseeeeeee

Answer 1

Hello! I'm here to hopefully help. I solved your equation and graphed it; here are my results. Practically what I did was that to solve the first equation I first isolated the "y" in the equation to transfer it to y=mx+b form; how you do that is to subtract the 3x from both sides of the equal sign. On the right it should cancel out the 3x and leave the negative 3x on the left side. Then you have to divide 6 to each number in the equation to fully isolate the "y" you would then get your equation simplified to "y = -1/2x + 2." Your slope would be the "-1/2" and the y-intercept would be the "2." I would suggest keeping the "-1/2" in fraction form to make it easier to solve, although it is also solvable to use decimals. For the next equation you do almost the exact same thing except with different numbers. You would once again isolate "y" by adding the "4" to each side of the equal sign to cancel out the left leaving the "2y" alone on the right side of the equation. Then your equation would be "2y = 4x + 6." Then once again you would divide each number by the "2" leaving you with the equation now simplified to "y = 2x + 3" which would be your final solution. Your slope would then be the "2" and your y-intercept would be the "3." Then you would use the "rise over run" method to put your equation into a graph.

Answer 2

well i cannot help u graph but u need to get them in y=mx+b form first

2x+y=4

y=-2x+4

2y-4x=6

2y=4x+6

y=2x+3

now that the problems are in y=mx+b form, u can graph them. the "b" is your y-intercept. you need to graph this first so what ever ur be is, put a point there on the y axis. then use your slope to plant your line. slope is rise/run. so for the top problem start at your y intercept and go down 2 and to the right 1. and for the bottem problem, start at your y intercept then go up 2 and to the right 1

HOPE THIS HELPED!