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RSB [31]
3 years ago
5

Carey earns $9.75 working part time on weekends. The table below shows the amount, a, Carey earns for working h hours.

Mathematics
1 answer:
shutvik [7]3 years ago
7 0
$29.25 in 3 hours. explanation: if he makes $9.75 in 1 hour then 9.75 x 3 (hours) would equal $29.25
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A candy dish contains 30 jelly beans and 20 gumdrops. Ten candies are picked at random. What is the probability that 5 of the 10
AveGali [126]

Answer:

The probability of drawing 5 gumdrops in 10 picks from the dish is 0.215

Step-by-step explanation:

A hypergeometric distribution is a discrete probability distribution that describes the probability of successes in draws with each draw being a success or failure, without replacement from a finite population size that contains exactly the same objects. The general formula is given as:

h(x) =\frac{({A}C_{x})({N-A}C_{n-x})}{^{N}C_{n}  }

where:

^{n}C_{r}=\frac{n!}{(n-r)!r!}

h(x)  is the probability of x successes,

n is the number of attempts,

A is the number of successes  

N is the number of elements

For this problem:

A = 30, x = 5, N = 50, n = 10

The probability of drawing 5 gumdrops in 10 picks from the dish P(x=5) is

P(x=5)=\frac{({30}C_{5})({50-30}C_{10-5})}{^{50}C_{10}  }\\P(x=5)=\frac{({30}C_{5})({20}C_{5})}{^{50}C_{10}  }

P(x=5)=\frac{\frac{30!}{(30-5)!5!}*\frac{20!}{(20-5)!5!}  }{\frac{50!}{(50-10)!10!} }\\P(x=5)=\frac{\frac{30!}{25!5!}*\frac{20!}{15!5!}  }{\frac{50!}{40!10!} }

P(x=5)=\frac{142506*15504}{1.207*10^{10} }=0.215

P(x=5) = 0.215

The probability of drawing 5 gumdrops in 10 picks from the dish is 0.215

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4 years ago
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Step-by-step explanation:

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4 years ago
At the bright-as-day light bulb factory, 5 out of each 136 bulbs produced are defective. If the daily production is 2720 bulbs,
lions [1.4K]

Answer:

100 lightbulbs

Step-by-step explanation:

Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)

Hope this helps!

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3 years ago
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