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Drupady [299]
3 years ago
9

What are the zeros of h(x)=x^4-18x^2+81

Mathematics
2 answers:
kykrilka [37]3 years ago
5 0

Answer:

zeros: x = -3, 3

Step-by-step explanation:

The zeros are the x values where the graph intersects the x-axis. to find the roots, replace the y with 0 and solve for x.

Mark Brainliest?

<h2>HOPE THIS HELPS!</h2>
vitfil [10]3 years ago
3 0

Answer: \\ Let \:  t  \: be \:   {x}^{2}  \\The  \: equation  \: is: {t}^{2}  - 18t + 81 = 0 (to \: find \: the \: zeros \: we \: set \: y = 0)\\ \Leftrightarrow \:  {(t - 9)}^{2}  = 0 \Leftrightarrow t - 9 = 0 \Leftrightarrow t =  {x}^{2}  = 9 \\  \Leftrightarrow x = 3 \: \vee \: x =  - 3 \\ \Rightarrow \: Zeros: - 3,3

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