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Drupady [299]
3 years ago
9

What are the zeros of h(x)=x^4-18x^2+81

Mathematics
2 answers:
kykrilka [37]3 years ago
5 0

Answer:

zeros: x = -3, 3

Step-by-step explanation:

The zeros are the x values where the graph intersects the x-axis. to find the roots, replace the y with 0 and solve for x.

Mark Brainliest?

<h2>HOPE THIS HELPS!</h2>
vitfil [10]3 years ago
3 0

Answer: \\ Let \:  t  \: be \:   {x}^{2}  \\The  \: equation  \: is: {t}^{2}  - 18t + 81 = 0 (to \: find \: the \: zeros \: we \: set \: y = 0)\\ \Leftrightarrow \:  {(t - 9)}^{2}  = 0 \Leftrightarrow t - 9 = 0 \Leftrightarrow t =  {x}^{2}  = 9 \\  \Leftrightarrow x = 3 \: \vee \: x =  - 3 \\ \Rightarrow \: Zeros: - 3,3

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a) C

b) B

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a) A linear equation can be written as y=mx+c where m is the slope and c is the intercept on the y-axis. The slope describes how y changes when x changes. A negative value means the it is a decreasing change. In our case, y is A and x is t. Thus, the slope of the equation is m=-0.062. This means that the area of glacier is decreasing by 0.062 \text{km}{}^2 = 62000 \text{m}{}^2 every year since 2000.

b) The A-intercept (= 16.2 \text{km}{}^2) represents the area covered when t=0. But t=0 starting from year 2000. This intercept then represents the area covered by glacier in the year 2000. Therefore, the area covered by glacier in 2000 was 16.2 \text{km}{}^2.

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Answer:

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