we have
----> inequality 1
The solution of the inequality 1 is the shaded area below the solid red line
The solution is the region D and region C
-----> inequality 2
The solution of the inequality 2 is the shaded area above the solid blue line
The solution is the region B and region C
The solution of the system is the common area
so
The solution is the region C
see the attached figure
therefore
the answer is the option C
Region C
Assuming ya meant
![\frac{csc(-x)}{1+tan^2(x)}](https://tex.z-dn.net/?f=%5Cfrac%7Bcsc%28-x%29%7D%7B1%2Btan%5E2%28x%29%7D)
to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos
for the pythaogreaon identity
![cos^2(x)+sin^2(x)=1](https://tex.z-dn.net/?f=cos%5E2%28x%29%2Bsin%5E2%28x%29%3D1)
divide both sides by
![cos^2(x)](https://tex.z-dn.net/?f=cos%5E2%28x%29)
![1+tan^2(x)=sec^2(x)](https://tex.z-dn.net/?f=1%2Btan%5E2%28x%29%3Dsec%5E2%28x%29)
since
![\frac{sin(x)}{cos(x)}=tan(x)](https://tex.z-dn.net/?f=%20%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%3Dtan%28x%29%20)
subsitute
![\frac{csc(x)}{sec^2(x)}](https://tex.z-dn.net/?f=%5Cfrac%7Bcsc%28x%29%7D%7Bsec%5E2%28x%29%7D)
recall that
![csc(x)=\frac{1}{cos(x)}](https://tex.z-dn.net/?f=csc%28x%29%3D%5Cfrac%7B1%7D%7Bcos%28x%29%7D)
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore
![csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)](https://tex.z-dn.net/?f=%20csc%28-x%29%3D%5Cfrac%7B1%7D%7Bcos%28-x%29%7D%3D%5Cfrac%7B1%7D%7Bcos%28x%29%7D%3Dcsc%28x%29)
so we get
![\frac{csc(x)}{sec^2(x)}](https://tex.z-dn.net/?f=%5Cfrac%7Bcsc%28x%29%7D%7Bsec%5E2%28x%29%7D)
decompose them into
![\frac{1}{cos(x)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bcos%28x%29%7D)
and
![\frac{1}{sin^2(x)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bsin%5E2%28x%29%7D)
to get
![\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B1%7D%7Bcos%28x%29%7D%7D%7B%5Cfrac%7B1%7D%7Bsin%5E2%28x%29%7D%7D)
multiply by
![\frac{sin^2(x)}{sin^2(x)}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%5E2%28x%29%7D%7Bsin%5E2%28x%29%7D)
to get
![\frac{sin^2(x)}{cos(x)}](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%5E2%28x%29%7D%7Bcos%28x%29%7D)
we can furthur simlify to get
![(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)](https://tex.z-dn.net/?f=%28%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%29%28sin%28x%29%29%3Dtan%28x%29sin%28x%29)
the expression simplifies to tan(x)sin(x)
Answer:
Number 1= 5th vertical line
number 2= 2nd vertical line
number 3= halfway between 2nd and 3rd vertical line
Step-by-step explanation:
Answer:
48 Miles
Step-by-step explanation:
I assume you are asking for the distance in miles between the two cities.
1 Inch = 8 Miles,
Then 6 Inches = 8 Miles * 6
If the cities are 6 inches apart, the actual distance is 48 miles.