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schepotkina [342]
3 years ago
11

Please give me the correct answer!!!

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

Step-by-step explanation:

this one is tricky    so b/c the lines are at 90 degees we know that the arcs are similar so set up the parts of the arcs equal to 360 degrees

360 = 130  + 130  + x + x

see each part of the circle ?

then use your mad algebra skilz

100 = 2x

50 = x  

:)  nice.. when I do the math , it seems easy , huh :DDD

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Read 2 more answers
5-x=12 help plss now
Zielflug [23.3K]

Answer:

x = -7

Step-by-step explanation:

5-x=12

To solve for x, you must first make the equation equal to x (to make x alone on one side).

5 - x = 12

-5         -5

-x = 7

-x(-1)=7(-1)

x = -7

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4 0
3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
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