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schepotkina [342]
3 years ago
11

Please give me the correct answer!!!

Mathematics
1 answer:
Neko [114]3 years ago
7 0

Answer:

Step-by-step explanation:

this one is tricky    so b/c the lines are at 90 degees we know that the arcs are similar so set up the parts of the arcs equal to 360 degrees

360 = 130  + 130  + x + x

see each part of the circle ?

then use your mad algebra skilz

100 = 2x

50 = x  

:)  nice.. when I do the math , it seems easy , huh :DDD

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Part A: Solve the equation 4(x + 5) = 9x + 4x − 34, and show your work. (5 points)
nasty-shy [4]

The value of x in the equation 4(x + 5) = 9x + 4x − 34 is 6 after solving and applying properties.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have equation:

4(x + 5) = 9x + 4x − 34  (Given)

4x +20 = 9x + 4x − 34    (Distributive Property)

4x +20 +34 -4x = 9x + 4x − 34 + 34 -4x   (Subtraction Property of Equality)

54 = 9x + 4x − 34 + 34 -4x  (Addition Property of Equality)

54 = 9x  (Combine Like Terms)

x = 54/9   (Division Property of Equality)

x = 6

Thus, the value of x in the equation 4(x + 5) = 9x + 4x − 34 is 6 after solving and applying properties.

Learn more about the linear equation here:

brainly.com/question/11897796

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3 0
2 years ago
What is the value of 3 in 6300 and 530
mojhsa [17]
The value of three in 6,300 is 3,000 because it is in the thousands place. The three in 530 is in the hundreds place making the value of three 300.  Hope that this helps you :D
5 0
3 years ago
Read 2 more answers
8th grade math . Pythagorran practice <br>​
Serhud [2]

The answers according to rows are:

  • ROW 1 : diameter of base = 10,  base area = 25π, volume of cylinder = 175π    volume of cone = \frac{175}{3}π
  • ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π
  • ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π

<h3>What is mensuration?</h3>

Mensuration is an aspect of geometry that deals with measurement of volumes and area.

Analysis:

Row 1

Diameter of base = 2 x radius = 2 x 5 = 10

Base area = πr^{2} = π(5)^{2} = 25\pi

Volume of cylinder = base area x height = 25π x 7 = 175π

Volume of cone  = 1/3 x volume of cylinder = 175π/3

Row 2

Base radius = base diameter/2 = 6/2 = 3

Base area = πr^{2} = π(3)^{2} = 9π

Volume of cone = 1/3 x base area x height

base area x height  = 3 x volume of cone

base area x height = 3 x 40π

Height = 120π/9π = 40/3

Cylinder volume = 3 x cone volume = 3 x 40π = 120π

Row 3

Base area = πr^{2}

36π =  πr^{2}

r2 = \sqrt{36}

r = 6

Base diameter = 2 x 6 = 12

Volume of cone  = 1/3 x base area x height

48π = 1/3 x 36π x height

Height = 4

Cylinder volume = 3 x 48 = 144π

In conclusion,

ROW 1 : diameter of base = 10,  base area = 25π, volume of cylinder = 175π

volume of cone = \frac{175}{3}π

ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π

ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π

Learn more about mensuration: brainly.com/question/18541562

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4 0
2 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
PLEASE HELP
Drupady [299]

Answer:

2x+8-2y

Step-by-step explanation:

4x-2x+5+3-2y

2x+8-2y

8 0
3 years ago
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