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3 years ago

Can anyone please help me out with this please I'm stuck on this question

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

3 0

34567890987654321234567898765432

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A parachutist's rate during a free fall reaches 180 kilometers per hour. What is this rate in meters per second? At this rate, h

Bumek [7]

Answer:

50 m/s

250 m

Step-by-step explanation:

180 km/hr × (1000 m / km) × (1 hr / 3600 s) = 50 m/s

50 m/s × 5 s = 250 m

5 0

3 years ago

Your cousin renews his apartment lease and pays a new monthly rent. His new rent is calculated by applying a discount of $50 to

nasty-shy [4]

Answer:

$1100

Step-by-step explanation:

Let the rent be x

Discounted rent

x - $50

Increase applied

Final rent:

(x - 50) + 10% = (x - 50)*1.1

We know this is equal to x + 5% = 1.05x, comparing now

1.1(x - 50) = 1.05x
1.1x - 1.05x = 55
0.05x = 55
x = 55/0.05
x = $1100

6 0

3 years ago

Woodland high school

lesantik [10]

That is correct because it’s a real high school

8 0

3 years ago

The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil

forsale [732]

Answer:

$IQR=4$

Step-by-step explanation:

We have been given a data set that represents the number of rings each person in a room is wearing as: 0, 2, 4, 0, 2, 3, 2, 8, 6. We are asked to find the interquartile range of the data.

Let us arrange our data points from least to greatest order.

0, 0, 2, 2, 2, 3, 4, 6, 8.

Let us find median of our data set. Since our data set has 9 data points, therefore, median of our given data set will be value of 5th term, that is 2.

Now let us find lower quartile, which is also known as the median of the data points to the left of median.

We have 4 data points to the left of our median, so our lower quartile will be average of 2nd and 3rd data point.

$Q_1=\frac{0+2}{2}=\frac{2}{2}=1$

Now let us find upper quartile of our given data set, which is the median of the data points to the right of median.

We have 4 data points to the right of the median, so our upper quartile will be the average of 7th and 8th data point.

$Q_3=\frac{4+6}{2}=\frac{10}{2}=5$

Since we know that interquartile range is the difference between upper and lower quartile.

$IQR=Q_3-Q_1$

$IQR=5-1$

$IQR=4$

Therefore, IQR of our given data set is 4.

8 0

3 years ago

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Select the correct answer.

Nezavi [6.7K]

Answer:

C 50 square centimeters

Step-by-step explanation:

3 0

2 years ago

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