So all you need to do if find the min of the function:
f(x)=0.04x^3-4x^2-176x
f'(x)=0.12x^2-8x-176
The only zero for this is x=84.105 <---first
Plug this into f(x) to get f(84.105)=-19300 <---second
So you write into the table that x = 1 then y will equal 1*1.5 which equal to 1.5. So under x = 1 in y table you write y = 1.5, and so on
Answer:
wow
Step-by-step explanation:
Answer:true
Step-by-step explanation:
The top line segment (12) is twice as long as the original, smaller (6), segment
