It is given that Mr Martin takes 12 minutes to drive his bus route without stopping on any of the stops.
On Tuesday, it took him 14 minutes when he stooped to take the passengers. He estimated that it takes 30 sec for each stop.
60 second = 1 minute.
30 second = 0.5 minutes.
Let us assume, there were x stops.
Since it takes him 12 minutes without stopping, 12 minutes here acts as a fixed time.
Total time is given by the equation
.... (1)
where t is the total time and x is the number of passengers.
To find the number of passengers, solve equation (1) for x ,
.... (2)
Plug y= 14 into equation number (2) gives 4 stops.
Answer:4025
Step-by-step explanation:
I think the answer would be 180
5*2=10 90*2=180
Answer:
true
Step-by-step explanation:
4(2)=8, and 4 times 2 =8
Answer:
a) 
: t=13 seconds
: t<13 seconds
b) At α= 0.01, one-tailed critical value is -2.33
c) Test statistic is −2,98
d) since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
Step-by-step explanation:
according to the web search, the question is missing some words, one part should be like this:
"A pit crew claims that its mean pit stop time ( for 4 new tires and fuel) is less than 13 seconds."
Let t be the mean pit stop time of the pit crew.
: t=13 seconds
: t<13 seconds
At α= 0.01, one-tailed critical value is -2.33
Test statistic can be calculated using the equation:
where
- X is the sample mean pit stop time (12.9 sec)
- M is the mean pit stop time assumed under null hypothesis (13 sec)
- s is the population standard deviation (0.19 sec.)
- N is the sample size (32)
Then 
≈ −2,98
since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
