All categories

3 years ago

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German.

2 answers:

8 0

If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.

Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.

MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.

Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.

n200080 [17]3 years ago

7 0

Answer:

Step-by-step explanation: so you do 15+17 because that isn’t the total amount of students.

You might be interested in

7 people are having dinner at a restaurant and decide to split the cheque evenly between them. If the check came to a total of $

DanielleElmas [232]

Answer:

The answer will be $54.5

Step-by-step explanation:

If 7 people slit $381.50 evenly, we will have

$381.50/7 = $54.5

7 0

4 years ago

It takes Matt 6 minutes to swim 12 laps in the pool. How many laps could he swim in 9 minutes?

pochemuha

Answer:

Step-by-step explanation:

6*2=12

9*2=18

Two laps per minute

4 0

3 years ago

Read 2 more answers

I need help ASAP!!!!!!!!!!!!!!!!!!!!!!!

HACTEHA [7]

Answer: -2.5

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago

34. HOME What's the Error? Nathan says

coldgirl [10]

Can’t see the coordinate plan so I can’t answer it

6 0

3 years ago

Read 2 more answers