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solong [7]
3 years ago
15

In a class, every student knows French or German (or both). 15 students know French, and 17 students know German.

Mathematics
2 answers:
vazorg [7]3 years ago
8 0
If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.

Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.

MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.

Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
n200080 [17]3 years ago
7 0

Answer:

Step-by-step explanation: so you do 15+17 because that isn’t the total amount of students.

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2 years ago
In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a
Art [367]

Answer:

The answer is "\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}"

Step-by-step explanation:

Given value:

Temp-maximum=18^{\circ}  

Temp. minimum = 3^{\circ}

It is halfway between 10 am and 10 pm to 4 am.  

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:  

T = A \cos B(t-C) + D, where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)

A = amplitude = \frac{(T_{max} - T_{min})}{2}\\\\

                       = \frac{(3 - 18)}{2}\\\\= - \frac{15}{2}\\\\ = -7.5

B = \frac{2 \pi}{24}\\\\

   = \frac{\pi}{12}

C = \text{ units translated to the right}= 4

D = y_{min} + amplitude = units \ translated \ up\\\\

D = 7.5 + 3 = 10.5

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T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5

6 0
3 years ago
The Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging
kirza4 [7]

Answer:

Step-by-step explanation:

given that the Chocolate House specializes in hand-dipped chocolates for special occasions. Three employees do all of the product packaging

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Pack      0.33          0.23    0.44 1

   

Defective 0.02 0.025    0.015  

   

Pack&def 0.0066 0.00575 0.0066 0.01895

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= P(II clerk) -P(II clerk and defective) = 0.23-0.00575=0.22425

b) the probability that a randomly selected box contains defective chocolate=P(I and def)+P(ii and def)+P(iiiand def)

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c) Suppose a randomly selected box of chocolates is defective. The probability that it was packaged by Clerk 3

=P(clerk 3 and def)/P(defective)

=\frac{0.0066}{0.01895} \\=0.348285

8 0
3 years ago
In a rectangle ABCD, A and B are the points (4,2) and (2,8) respectively l. Given that the equation of AC is y=x-2. Find the equ
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Hello,

A=(4,2)
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(AB)≡y-2=(x-4)*(8-2)/(2-4) ==> y=-3x+14
(BC)≡y-8=(x-2)*1/3 ==> y=1/3 x+22/3



4 0
2 years ago
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