<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.
So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y
When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)
When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)
Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23
Thus we can say the number of chairs increase by 23 as compared to a normal day.
</span>
Answer:
y=6
Step-by-step explanation:
Answer:
.
Step-by-step explanation:
The minimun distance between a point and a plane is the perpendicular distance. The formula is
d = 
where 
, A=4, B=3, C=1 and D=-10. So, the distance is
d = 
d = 
d = .
Answer:
f(n+1) = 13
Step-by-step explanation:
- We know that f(1) = 15
- So we can substitute this for f(n)-3
- With this:
- f(n+1) = f(1) -3
- f(n+1) = 15-2
- f(n+1) = 13
It would be 384.58, or 384.57909
