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suter [353]
3 years ago
10

Does anybody have their geometry notebook for E2020? I need it to get credit for the course but I lost mine.

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

Sorry, I don't have one.

Step-by-step explanation:

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3z-4=6z-17 how do solve
Maru [420]
3z-4=6z-17
-3z-4=-17 (subtracted the 6z from both sides)
-3z=-13 (added the 4 to both sides)
z=\frac{-13}{-3z} (divided both sides by -3z)
z=\frac{13}{3}
5 0
4 years ago
Read 2 more answers
9 = -3 + n + 2n what does n equal ?
coldgirl [10]

Step-by-step explanation:

9=-3+n+2n

9+3=n+2n

12=3n

n=12/3

n=4

5 0
3 years ago
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The ratio of oil to vinegar in a certain salad dressing is 8 : 5. How much oil must be blended with 7 liters of vinegar for that
Radda [10]

Answer:

1:4

Step-by-step explanation:

hope it help

6 0
3 years ago
..vertex: (4, -1)<br> f(3) = -6
s344n2d4d5 [400]

Answer:

\huge\boxed{f(x)=-5(x-4)^2-1=-5x^2+40x-81}

Step-by-step explanation:

The vertex form of an equation of a parabola:

f(x)=a(x-h)^2+k

(h;\ k) - vertex

We have

vertex (4;\ -1)\to h=4;\ k=-1

f(3)=-6

Therefore we have:

f(x)=a(x-4)^2+(-1)=a(x-4)^2-1

Substitute x=3 and f(3)=-6

a(3-4)^2-1=-6\qquad|\text{add 1 to both sides}\\\\a(-1)^2=-6+1\\\\a(1)=-5\\\\a=-5

Finally:

f(x)=-5(x-4)^2-1=-5(x^2-2(x)(4)+4^2)-1\\\\=-5(x^2-8x+16)-1=-5x^2+(-5)(-8x)+(-5)(16)-1\\\\=-5x^2+40x-80-1=-5x^2+40x-81

4 0
4 years ago
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 20%
zhuklara [117]

Answer:

a. 5% of the employees will experience lost-time accidents in both years

b. 24% of the employees will suffer at least one lost-time accident over the two-year period

Step-by-step explanation:

a. What percentage of the employees will experience lost-time accidents in both years?

20% last year, of those who suffered last year, 25% during this year. So

p = 0.2*0.25 = 0.05

5% of the employees will experience lost-time accidents in both years.

b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?

5% during the two years.

10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.

So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.

First year yes, not on the second.

75% of 20%. So, total:

0.05 + 0.05*0.8 + 0.75*0.2 = 0.24

24% of the employees will suffer at least one lost-time accident over the two-year period

3 0
3 years ago
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