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2 years ago

14

The number of wins in the American Baseball League, Central Division, for a recent year is given in the table. Find the mean num

ber of wins. Round your answer to one decimal place.
The mean number of wins for the five teams is ______wins?

1 answer:

Strike441 [17]2 years ago

3 0

Answer:

add sll number so you will get answer

dd

Step-by-step explanation:

You might be interested in

In triangle NOP, Np is extended through Point P to Point Q, m < NOP =(x+17) degrees, m< PNO =(2x-4) degrees, and m< OPQ

Zigmanuir [339]

To find the measure of angle OPQ, we have two equations...
y+5x-17=180 because angles OPN and OPQ are supplementary...
AND
x+17+2x-4+y=180 because the total degrees of a triangle must add up to 180.
The equations...
5x+y=197
3x+y=167
solce the system of equations...
x=15
y=122
Since we wanted to solve for y, 122 is the answer.
The measure of angle OPQ is 122.

Sorry this took forever. The website is hard to use because I'm used to using the app:)

Best of wishes!

6 0

3 years ago

ANSWER CORRECTLY PLEASE

Harlamova29_29 [7]

Answer:

88/4 and 48/4

Step-by-step explanation:

88 + 48 = 136

136/4 = 34

5 0

3 years ago

Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

$-3Y=x^2+12x+15$

Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

8 0

3 years ago

The sun produces 3.8x10^27 joules of energy per second. How much energy is produced in a year? (Note: a year is approximately 31

Slav-nsk [51]

About 1.204972095x10^20 joules in a year

3 0

2 years ago

What is the taxidistance between (2,11) and (7,10)<br> 4<br> 6<br> 7<br> 26

Scilla [17]

X difference: 7-2 = 5 y difference: 11-10 = 1 Add up those results: 5+1 = 6

Answer Is 6

4 0

3 years ago