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mart [117]
3 years ago
10

Joy and Peter were each walking along a straight road. Joy walked 1800 meters in 1/3 hour. Peter walked 1/2 of joy's distance in

1/5 hour.
1. What was joy's average walking speed
2. How much did Peter walk in 1/5 hour
3. What is peter's average walking speed
4. Joy walks how much meters/hours faster, slower, or as fast as
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
The answer is 3 because it says how much joy walked and not Peter , you’re trying to figure out what’s peters average walking speed
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Find the perimeter of each polygon 4cm
andriy [413]
Your answer is 12!!!!!
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3 years ago
X+2y=19 and x+y=13 in substitution methood​
densk [106]
X=7, y=6. that’s your answer!
3 0
2 years ago
Mrs. JOHNSON paid $40.68 for 3kg of shrimp. What’s the cost of 1 kilogram of shrimp?
Goshia [24]

Answer:

It is 13.56

Step-by-step explanation:

You would have to divide 40.68 by 3. 3 goes 1 time into 4 so it is 10.

4 0
3 years ago
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YZ has endpoints Y(0,5) and Z (12,3). Find the length of YZ to the nearest tenth.
Alex Ar [27]
Using the formula;
 d(Y, Z) =\sqrt{(xZ - xY)^2 + (yZ - yY)^2

You should get 12.1655 or 12.2 units.

Hope this helps you with Coordinate Solving!

4 0
4 years ago
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The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb,
NNADVOKAT [17]

Answer:

bbbb,

bbbg, bbgb, bgbb, gbbb,

bbgg, bgbg, bggb, gbgb, gbbg, ggbb,

bggg, gbgg, ggbg, gggb,

gggg

Step-by-step explanation:

3 children: bbb, bbg, bgb, gbb, bgg, gbg, ggb, ggg

4 children: bbbb, bbbg, bbgb, bgbb, gbbb, bbgg, bgbg, bggb, gbgb, ggbb, bggg, gbgg, ggbg, gggb, gggg

You need to take a methodological approach;

The 2 easiest are the possibility of all boys and all girls;

Then consider 3 boys and 1 girl:

bbbg, bbgb, bgbb, gbbb

Then 2 boys and 2 girls:

bbgg, bgbg, bggb, gbgb, gbbg, ggbb

Lastly, 1 boy and 3 girls:

bggg, gbgg, ggbg, gggb

In total, there are 16 possibilities

P.S. interesting to note is that the number of possibilities here follows the pattern of Pascal's triangle:

       1

     1   1

   1  2  1

 1  3  3  1

1  4  6  4  1

The last row is relevant here;

There is 1 possibility where there are 4 boys;

There are 4 possibilities (in terms of the order of birth) where there are 3 boys and 1 girl;

There are 6 possibilities where there are 2 boys and 2 girls

There are 4 possibilities where there is 1 boy and 3 girls;

There is 1 possibility where there are 4 girls;

The pattern ∴ is 1 4 6 4 1, as the 5th row of Pascal's triangle reads;

If your talking about 3 children, it would match the 4th row of Pascal's triangle;

So, 1 possibility of 3 boys;

3 possibilities of 2 boys and 1 girl;

3 possibilities of 1 boy and 2 girls;

And 1 possibility of 3 girls;

If your talking about 10 children, it would match the 11th row of Pascal's triangle.

(Maths can be so cool XD)

7 0
3 years ago
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