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mart [117]
3 years ago
10

Joy and Peter were each walking along a straight road. Joy walked 1800 meters in 1/3 hour. Peter walked 1/2 of joy's distance in

1/5 hour.
1. What was joy's average walking speed
2. How much did Peter walk in 1/5 hour
3. What is peter's average walking speed
4. Joy walks how much meters/hours faster, slower, or as fast as
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0
The answer is 3 because it says how much joy walked and not Peter , you’re trying to figure out what’s peters average walking speed
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Answer:

\sf x=2+\sqrt{6},\:x=2-\sqrt{6}

Explanation:

\sf y = x^2 -4x

given that y = 2

\sf x^2 -4x = 2

\sf x^2 -4x -2 = 0

using quadratic formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \    \ \ when  \   ax^2 + bx + c = 0

\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}

\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}

\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}

in decimals:

\rightarrow \sf x=4.45 , \ -0.45

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zmey [24]

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Step-by-step explanation:

i am pretty sure this is correct:)

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