F(x)= y-x/x^2-16 (that’s a fraction; and the ^ indicates the 2 is a exponent)

Mathematics

1 answer:

bulgar [2K]3 years ago

4 0

Answer:

= 1/x^2

Step-by-step explanation:

Possible derivation:

d/dx(-16 - 1/x + y)

Differentiate the sum term by term and factor out constants:

= d/dx(-16) - d/dx(1/x) + d/dx(y)

The derivative of -16 is zero:

= -(d/dx(1/x)) + d/dx(y) + 0

Simplify the expression:

= -(d/dx(1/x)) + d/dx(y)

Use the power rule, d/dx(x^n) = n x^(n - 1), where n = -1.

d/dx(1/x) = d/dx(x^(-1)) = -x^(-2):

= d/dx(y) - -1/x^2

Simplify the expression:

= 1/x^2 + d/dx(y)

The derivative of y is zero:

= 1/x^2 + 0

Simplify the expression:

Answer: = 1/x^2

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Therefore, we have;

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