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Serga [27]
2 years ago
7

F(x)= y-x/x^2-16 (that’s a fraction; and the ^ indicates the 2 is a exponent)

Mathematics
1 answer:
bulgar [2K]2 years ago
4 0

Answer:

= 1/x^2

Step-by-step explanation:

Possible derivation:

d/dx(-16 - 1/x + y)

Differentiate the sum term by term and factor out constants:

= d/dx(-16) - d/dx(1/x) + d/dx(y)

The derivative of -16 is zero:

= -(d/dx(1/x)) + d/dx(y) + 0

Simplify the expression:

= -(d/dx(1/x)) + d/dx(y)

Use the power rule, d/dx(x^n) = n x^(n - 1), where n = -1.

d/dx(1/x) = d/dx(x^(-1)) = -x^(-2):

= d/dx(y) - -1/x^2

Simplify the expression:

= 1/x^2 + d/dx(y)

The derivative of y is zero:

= 1/x^2 + 0

Simplify the expression:

Answer: = 1/x^2

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Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len
FromTheMoon [43]

Width of the miniature model = 3\frac{3}{4} inches

Length of the miniature model = 5\frac{1}{2} inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x

$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x

$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}

Do cross multiplication.

$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}

$\Rightarrow{\frac{15}{4}x =\frac{165}{2}

$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0
3 years ago
How many kilograms are in 30 pounds
Ghella [55]
30 pound in kilograms are 13.61 kilograms
6 0
2 years ago
Read 2 more answers
Melanie connected a brown garden hose, a green garden hose, and a black garden hose to make one long hose. The brown hose is 10.
natta225 [31]

Answer:

35.65 feet

Step-by-step explanation:

Melanie connected a brown garden hose , a green garden hose and a black garden hose to make one long hose

The brown hose is 10.75 feet

The green hose is 16.4 feet

The black hose is 8.5 feet

Therefore the farthest distance that the one hose can reach can be calculated as follows

= 10.75 + 16.4 + 8.5

= 35.65 feet

Hence the farthest distance that one hose can reach is 35.65 feet

3 0
3 years ago
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