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ra1l [238]
3 years ago
6

What is the solution of log2x + 6 144 = 2?

Mathematics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

x=-3

Step-by-step explanation:

2x+6144=2

2x=2-6144

2x=-6142

x=-6142÷2

x=-3071

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A bag contains white marbles and yellow marbles, 16 in total. The number of white marbles is 5 less than 2 times the number of y
bija089 [108]

Answer:

9 White marbles are present in the bag.

Step-by-step explanation:

Let the number of White marbles present in the bag be X and number of Yellow marbles present be Y .

Then according to the question ,

X + Y = 16      -(1)        (As total marbles are 16)

Also,

X = 2Y - 5      -(2)

From Equation 1 , X = 16 - Y  , Comparing with Equation 2 , we get,

16 - Y = 2Y - 5

3Y = 21.

Y = 7.

So, X = 16 - Y = 16 - 7 = 9.

Thus, 9 White marbles are present in the bag.

8 0
3 years ago
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The answer is 5. Mode is the number that shows up the most times
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3 years ago
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nadezda [96]

Answer its 24x8

Step-by-step explanation:

4 0
2 years ago
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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

.

.

.

Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
2 years ago
Giving Brainliestttttttt to first answer that’s correct!
Luba_88 [7]

Answer:

I think C sorry if wrong

7 0
3 years ago
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