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love history [14]
3 years ago
13

Bruh- can someone pls help me out kindly I will give 13 points

Mathematics
2 answers:
kari74 [83]3 years ago
8 0

Answer: this is really simple so we know that the coordinate points have an X and a Y value we see that (4,-2)

Step-by-step explanation:

We just plug it in for example

-2 for Y because it’s the Y value and 4 for x because it’s the X value

-2=1/2(4)-4

*we know that half of 4 is 2*

now the equation is -2=2-4

finally we just subtract 2-4 which is -2

-2=-2 so the equation is right

ycow [4]3 years ago
7 0

Answer:

\huge\boxed{\texttt{Yes. Explanation for why.}}

Step-by-step explanation:

If we have the equation y = \frac{1}{2}x - 4 and we want to test if the point (4,–2) satisfies the equation, we can plug the x and y values into the equation and see if they make the equation true.

4 is the x value, -2 is the y.

-2 = (\frac{1}{2}\cdot4)-4

-2 = 2 - 4

-2 = -2

So this does satisfy the equation.

Hope this helped!

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A grocery store sells 6 bottles of water for $4 and 18 bottles for $10. Is the cost of the water proportional to the number sold
kirill115 [55]

Answer:

Non Proportional​

Step-by-step explanation:

Make a proportion:

For example say you want to test out how many bottles of water you can buy for $10

Proportion:

4 - 6

10 - ?

Solve: 10×6÷4=15

So technically, you could only get 15 bottles for $10. Therefore, this is a non proportional problem.

5 0
3 years ago
Find the distance between the pair of points: (2,6) and (0,−3).
FrozenT [24]

Answer:

d = √85

Step-by-step explanation:

d^2 = (X2 - X1)^2 + (Y2 - Y1)^2

= (2 - 0)^2 + (6 + 3)^2

= 4 + 81

d = √85

3 0
3 years ago
What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
3 years ago
Read 2 more answers
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Tamiku [17]
You solve this by using google.com or YouTube.com

Or just pay attention in class to get this.   
3 0
3 years ago
Does anybody know this??????
aniked [119]
The correct answer is 196 or Option A.
The explanation is just as complicated as the question.
7 0
3 years ago
Read 2 more answers
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