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lina2011 [118]
3 years ago
11

Find the parametric equations for the line that is tangent to the given curve at the given parameter (3cost)i (t^4 -3sint)j

Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

Following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

In the given equation, when the point t=0

So,

\to r(0) = (3 \cos 0)i + (0^4 - 6 \sin 0)j + (2e^{3\times 0})k)

           = (3 \times 1)i + (0 - 0)j + (2e^{0})k)\\\\ = 3i +  0j + (2 \times 1)k)\\\\ = 3i +  0j + 2k \\

The value of the coordinates are 3, 0, 2 . so, the equation of the line is:

\to \frac{(x-3)}{3 \cos \ t} = \frac{(y-0)}{(t^{4}-6 \sin \ t)} = \frac{(z-2)}{2e^{3t}}=k

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Answer:

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6 cm = 11.04 miles

Step-by-step explanation:

To find the distance, set up a proportion. A proportion is two equal ratios set equal to each other. We form the ratios by using corresponding values. We write a ratio of \frac{map}{real world} and simplify.

We know \frac{map}{real world}=\frac{0.5in}{2.3 miles}. We know the distance on the map is 12 cm and 6 cm whish converts to 4.7 inches and 2.4 inches. We can write \frac{4.7in}{xmiles} and  \frac{2.4in}{xmiles}

We set them equal.

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and

2.3(2.4)=0.5(x)\\5.52=0.5x\\\frac{5.52}{0.5}=\frac{0.5x}{0.5} \\11.04 miles=x

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Step-by-step explanation:

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