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lina2011 [118]
3 years ago
11

Find the parametric equations for the line that is tangent to the given curve at the given parameter (3cost)i (t^4 -3sint)j

Mathematics
1 answer:
ale4655 [162]3 years ago
5 0

Answer:

Following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

In the given equation, when the point t=0

So,

\to r(0) = (3 \cos 0)i + (0^4 - 6 \sin 0)j + (2e^{3\times 0})k)

           = (3 \times 1)i + (0 - 0)j + (2e^{0})k)\\\\ = 3i +  0j + (2 \times 1)k)\\\\ = 3i +  0j + 2k \\

The value of the coordinates are 3, 0, 2 . so, the equation of the line is:

\to \frac{(x-3)}{3 \cos \ t} = \frac{(y-0)}{(t^{4}-6 \sin \ t)} = \frac{(z-2)}{2e^{3t}}=k

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You roll a standard number cube. Find P (number less than 4).
Serggg [28]
A standard number cube has 6 sides.

P is any number less than 4 (or 3,2, and 1).

3, 2, and 1 are 3 numbers

Place the number 3 over the amount of numbers there is.

3/6. 

Simplify. Divide 3 from the numerator and denominator.

(3/6)/(3/3) = 1/2

1/2, or (B) is your answer

hope this helps!
5 0
3 years ago
Laptops that sell for $660 are on sale with a percent discount of 7%. Find the sale price. Round your answer to the nearest cent
ivann1987 [24]

Answer:

$613.80

Step-by-step explanation:

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3 years ago
(y= –2x – 5<br> Ty= 2x – 2
Elden [556K]

Answer:

t=2x-2/-2x-5

Step-by-step explanation:

y=-2x-5

ty= 2x-2

add the y value in

t-2x-5=2x-2

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4 0
3 years ago
Cora's dad has asked Cora and her little brothers to rake the leaves in their yard. They rake all afternoon and fill a number of
Sever21 [200]

Answer:

11

Step-by-step explanation:

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4 0
3 years ago
How do you Graph y-3=1/3(x+1)
jekas [21]

Answer:

You can find the point of intersection of the line with the y-axis and the  the point of intersection of the line with the x-axis. See the graph attached.

Step-by-step explanation:

Find the intersection with the y-axis. Substitute x=0 into the equation and solve for y:

y-3=\frac{1}{3}(x+1)\\\\y-3=\frac{1}{3}(0+1)\\\\y-3=\frac{1}{3}(1)\\y=\frac{1}{3}+3\\\\y=\frac{10}{3}

y≈3.33

Find the intersection with the x-axis. Substitute y=0 into the equation and solve for x:

y-3=\frac{1}{3}(x+1)

0-3=\frac{1}{3}(x+1)\\(-3)(3)=x+1\\-9-1=x\\x=-10

Now, you know that the line passes through the point (0,3.33) and (-10,0). Now you can graph the function. (Observe the graph attached)

6 0
3 years ago
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