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3 years ago

Help please need this answer

Mathematics

2 answers:

fredd [130]3 years ago

7 0

Answer:

(5,4) is the solution

Step-by-step explanation:

2x + y = 14 --> y = -2x + 14

Substitute y = -2x + 14 into 3x - 2y = 7

3x - 2( -2x + 14) = 7

3x + 4x - 28 = 7

7x = 35

x = 5

y = -2(5) + 14

y = -10 + 14

y = 4

Answer (5 , 4)

Whitepunk [10]3 years ago

3 0

Answer:

C) (5,4)

Step-by-step explanation:

So 4x+2y=28. So now we can write 7x=35. X=5. So now we can plug it in! So y=4.

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Vikki [24]

Answer:

b = 43

Since 43 is congruent to b

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3 years ago

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równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

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20 = 25 - 5 t

t = 1 s

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2 years ago

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postnew [5]

Answer:

Step-by-step explanation:

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3 years ago

What is the range of the data below? 15, 19, 17, 17, 14, 13, 18, 21, 16, 14

Black_prince [1.1K]

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3 years ago

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You could win a giant jar of M&Ms, if only you could guess how many are in the jar. You find a smallerjar such that the gian

sleet_krkn [62]

Answer:

There are 7360 M&Ms in larger jar.

Step-by-step explanation:

We are given the following in the question:

A giant jar is such that it is exactly four times times the smaller jar in dimensions.

If r and h is the radius and height of the cylindrical jar respectively, then the dimensions of the larger are:

$R = 4r\\H=4h$

Number of M&Ms in smaller jar = 115

Volume of smaller jar =

$v = \dfrac{1}{3}\pi r^2 h$

Volume of larger jar =

$V =\dfrac{1}{3}\pi R^2 H=\dfrac{64}{3}\pi r^2 h$

Number of M&Ms in larger jar:

$v = \dfrac{1}{3}\pi r^2 h\rightarrow 115\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 115\times 64\\\\V=\dfrac{64}{3}\pi r^2 h\rightarrow 7360$

Thus, there are 7360 M&Ms in larger jar.

6 0

3 years ago