Answer:
no solution
Step-by-step explanation:
u cant multiply when there is an equal
<h3>
Answer: 144</h3><h3>
Step-by-step explanation:</h3><h3 />
Since, the first 9 multiple of 4 starts from 0 are,
0, 4, 8, 12, 16, 20, ................
Which is an AP,
Having the first term, 
And, the successive difference, d = 4,
Since, the sum of the n term of an AP,
![S_n = \frac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D)
Hence the sum of 9 term of the above AP,
![S_9 = \frac{9}{2}[2\times 0 + (9-1)\times 4]](https://tex.z-dn.net/?f=S_9%20%3D%20%5Cfrac%7B9%7D%7B2%7D%5B2%5Ctimes%200%20%2B%20%289-1%29%5Ctimes%204%5D)
The slope is 1.3. The whole equation is y=1.3x+4.9
(x+1)(2x+3)
Hope this helps you
The line from the point to its reflection should be perpendicular.If we imagine a line from (5,7) to (2,2), it would have a slope of (2-7)/(2-5) = 5/3.
For that line to be perpendicular to y=-2/5x+6, their slopes should be each other's negative reciprocals.
-2/5 negative reciprocal is 5/2, which is not equal to our calculated 5/3, so (2,2) cannot be the reflected point. Evan was wrong.
Q1-74: AB have slope 6/5, C has -5/6, D 6/5, E -5/6 again.
