Create a list of 8 values with a mean of 26. Justify your response.

1 answer:

8 0

Essentially, if want to list some values with a given mean, you can assume that they all have this value, so a correct answer will be:

26,26,26,26,26,26,26,26,

You can also vary the values, as long as their sum remains the same (the sum and the number of values decide the mean).

For example, you can add one and remove one:
27,25,26,26,26,26,26,26,

You might be interested in

Choose the proper tools with the correct endpoints then click and drag the endpoints to the correct location.

qwelly [4]

X < = 1 or x > 8

closed circle on 1, shaded to the left
open circle on 8, shaded to the right

6 0

3 years ago

Can someone show me step by step on how to solve this, I'd very much appreciate the help. In the figure below, what is the value

klemol [59]

Answer:

Step-by-step explanation:

According to the Exterior Angle Theorem, the exterior angle is equal to the sum of the interior angles opposite from the exterior angle. In other words:

$68+x=100$

Solve for x. Therefore:

$m\angle x=32^\circ$

Our answer is D.

5 0

3 years ago

Read 2 more answers

This super easy yall

baherus [9]

Answer:

the answer would be 180 degrees

Hope this helps :)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an

poizon [28]

Answer:

We have that $B = 0.3$ .

$0.3 = b + (A \cap B)$

However, b is a probability, which means that it cannot be negative. So no, P(A ∩ B) cannot be 0.5. It can, at most, be 0.3.

Step-by-step explanation:

Event A:

Probability that a student has a Visa card.

Event B:

Probability that the student has a MasterCard.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student has a Visa card but not a MasterCard and $A \cap B$ is the probability that a student has both these cards.