i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Well in order to find how many toy cars were in each package you would need to divide the number of toy cars by the number of packages. So your expression would be p / 6.
Answer:
352x^2
Step-by-step explanation:
40\times 1.25x\times 2.20x\times 3.2040×1.25x×2.20x×3.20
(40)1.25x2.20x3.20
+ − . ln > <
× ÷ / log ≥ ≤
( ) logx = %
1 Take out the constants.
(40\times 1.25\times 2.20\times 3.20)xx(40×1.25×2.20×3.20)xx
2 Simplify 40\times 1.2540×1.25 to 5050.
(50\times 2.20\times 3.20)xx(50×2.20×3.20)xx
3 Simplify 50\times 2.2050×2.20 to 110110.
(110\times 3.20)xx(110×3.20)xx
4 Simplify 110\times 3.20110×3.20 to 352352.
352xx352xx
5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
352{x}^{2}352x
2
Done
Answer:
Step-by-step explanation:
Given the system of the equations
solving by elimination method
solve for 
:
Solve 
for x:
Therefore,
Answer: The answer is around 16.66%
