A school P is 16km due west of a school Q. what is the bearing of Q from P
1 answer:
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
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Step-by-step explanation:
We want to graph:
We first graph the parent function
This parent function has x-intercept at (1,0) and it is asymptotic to the y-axis.
We then shift the graph of the parent function 3 units right, to obtain the graph of
The new x-intercept will be (4,0) and vertical asymptote will now be x=3.
See attachment.
