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Tom [10]
2 years ago
6

What is the greatest common factor of 14 and 18? (Worth 20 points)

Mathematics
2 answers:
Tatiana [17]2 years ago
6 0
Factors of 8 are; 1,2,4,8 Factors of 12 are; 1,2,3,6,9,12 The first # in both set of Factors is the GCF.
mina [271]2 years ago
4 0
The Greatest Common factor of 14 and 18 is 2. Here is my work ~

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Solve each system of equations algebraically. For each one, explain what the solution (or lack thereof) tells you
Paul [167]

Answer:

a: no solutions

b: (2, 3)

Step-by-step explanation:

a:

In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.

b:

Since both of the equations are equal to y, we can set them equal to each other:

\frac{1}{2}x^2+1= 2x-1\\x^2 + 2 = 4x - 2\\x^2-4x+4=0

We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):

(x-2)^2 = 0

x = 2

Now, to find y, plug-in x to any of the equations:

y = 2*2-1 = 3

Therefore, the solution to this system of equation is (2, 3)

I hope this helped.

4 0
3 years ago
What is the consequence of L'hopital's Rule?​
arlik [135]

Answer:

So, L'Hospital's Rule tells us that if we have an indeterminate form 0/0 or ∞/∞ all we need to do is differentiate the numerator and differentiate the denominator and then take the limit. (Brainliest? :3)

Step-by-step explanation:

8 0
3 years ago
If a4 = 625, what does (a) equal?
Reika [66]

I'm assuming you meant to write a^4 = 625.

If that is the case, then note how 625 = 25^2, and how a^4 is the same as (a^2)^2

So we go from this

a^4 = 625

to this

(a^2)^2 = 25^2

Apply the square root to both sides and you'll end up with: a^2 = 25

From here, apply the square root again to end up with the final answer: a = 5 or a = -5

As a check:

a^4 = (-5)^4 = (-5)*(-5)*(-5)*(-5) = 25*25 = 625

a^4 = (5)^4 = (5)*(5)*(5)*(5) = 25*25 = 625

Both values of 'a' work out

4 0
3 years ago
HELP ME THANKS +×+
Tresset [83]

Answer:

hypotenuse =  \sqrt{ {height}^{2} +  {adjacent}^{2}  }  \\  =  \sqrt{ {11}^{2}  +  {60}^{2} }  \\  =  \sqrt{3721}  \\  = 61 \: inches

4 0
3 years ago
Read 2 more answers
In the figure below, ∠ABC ≅ ∠DEC and ∠GFE ≅ ∠DCE. Point C is the point of intersection between segment AG and segment BD, while
I am Lyosha [343]

Answer:

See Below.

Step-by-step explanation:

We are given that:

\angle ABC \cong \angle DEC\text{ and } \angle GFE \cong \angle DCE

By vertical angles:

\displaystyle \angle DEC\cong \angle GEF\text{ and } \angle DCE\cong \angle ACB

Hence, by substitution:

\displaystyle \angle ABC\cong \angle GEF\text{ and } \angle GFE\cong \angle ACB

Then by Angle-Angle Similarity:

\Delta ABC \sim \Delta GEF

8 0
3 years ago
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