Let a = longest side <em> (Establishing labels)</em>
let b = shortest side
let c = third side
P = 14.5 <em> (Given)</em>
a = 6.2
b = 1/2(a)
P = a + b + c
P = 6.2 + 3.1 + c <em>(Fill in given info in equation)</em>
P = 9.3 + c <em>(Simplify)</em>
14.5 = 9.3 + c <em>(Simplify)</em>
c = 14.5 - 9.3 <em>(Solve)</em>
c = 5.2
Hope this made sense!
Given:
wild turkey ; 12 in the first hour and cumulative number increases by 40% per hour
white-tail deer ; 18 in the first hour and 10 deer each hour after that.
wild turkery: 12 * (1.40)^n-1 ; n is the number of hour
white-tail deer: 18 + 10^n-1 ; n is the number of hour
n wild turkey white-tail deer
1 12 18
2 17 28
3 24 38
4 33 48
5 46 58
6 65 68
7 90 78
It would be hour 7 after sunrise that the cumulative count of the turkeys first exceed the cumulative count of the deer.
Answer:
x is 2
Step-by-step explanation:
you need to do 10-6 is 4 then 2x? is 4
Answer:
what
Step-by-step explanation:
Answer:
y=15/7x-4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(11-(-4))/(7-0)
m=(11+4)/7
m=15/7
y-y1=m(x-x1)
y-(-4)=15/7(x-0)
y+4=15/7(x)
y+4=15/7x
y=15/7x-4
