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Rudiy27
3 years ago
12

An object at rest will stay at rest, and an object in motion will stay in motion becuase of

Chemistry
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

inertia

Explanation:

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5 0
3 years ago
Determine the ph of a 0. 35 m aqueous solution of CH3NH2 (methylamine). The kb of methylamine is?
guajiro [1.7K]

The pH of 0.35 M of CH₃NH₂ is 12.09 and the k_b for methylamine is 4.4 x 10⁻⁴.

<h3>What is pH?</h3>

pHis the quantitative measure of acidity and basicity of an aqueous or other liquid solution. The scale range goes from 0 to 14. Water has a pH of 7 and is neutral in nature.

<h3>What is dissociation constant?</h3>

The dissociation constant is an equilibrium constant that describes the dissociation or ionization of a base or an acid

k_a describes the dissociation of an acid

k_b describes the dissociation of a base

For methylamine,

CH_3NH_2 + H_2O\Leftrightarrow CH_3NH_3^+ + OH^-

Initial concentration of methylamine = 0.35 M

Initial concentration of products = 0

Let, at equilibrium concentration of CH₃NH₂ = 0.35 - x

Then, concentration of CH₃NH₃⁺ and OH⁻ is x and x respectively

k_b = \frac{[CH_3NH_3^+] [OH^-]}{[CH_3NH_2]}

The dissociation constant for methylamine, k_b = 4.4 x 10⁻⁴

4.4 \times 10^-^4 = \frac{x.x}{0.35} \\x^{2} = 4.4 \times 10^-^4 \times 0.35\\x^{2}  = 1.54  \times 10^-^4 \\

x =0.0124

pOH = -log[OH] = -log(0.0124) = 1.91

pH + pOH = 14

pH = 14 - 1.91 = 12.09

Thus, the pH of methylamine is 12.09 and k_b is 4.4 x 10⁻⁴

Learn more about pH:

brainly.com/question/172153

#SPJ4

7 0
2 years ago
In the second footnote it was pointed out that mass and energy are alternate aspects of a single entity called mass-energy. The
Artemon [7]

Answer:

The corresponding mass change in this process is 1.9055\times 10^{-8} g

Explanation:

E= mc^2,

where :

E is energy released with respect to mass

m is change mass

c is the speed of light.

2.096 g of hydrogen molecules combined with 96.000 g of oxygen molecules to form water and released energy E.

E=1.715\times 10^3 kJ=1.715\times 10^6 J

Mass change in this process = m

1.715\times 10^6 J=m\times (3\times 10^8 m/s)^2

m=1.9055\times 10^{-11} kg=1.9055\times 10^{-8} g

The change in mass calculated from Einstein equation is small that its effect on formation of product will be negligible.Hence, law of conservation of mass holds correct for chemical reactions.

4 0
3 years ago
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