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4 years ago

Which of the following laws states that the volume of a gas and the amount of a gas in moles are directly proportional?

1 answer:

muminat4 years ago

4 0

You haven't provided a list of answers but the law to which states "volume of gas is proportional to the number of moles of gas," is Avogadro's law.

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How many covalent bonds can each carbon atom form?

rodikova [14]

Carbon can form a maximum of 4 covalent bonds because it has 4 valence electrons i.e. 4 outer electrons.

5 0

4 years ago

Read 2 more answers

How do you know an organism is a heterotroph? Name three heterotrophs

Reptile [31]

Answer:

1. Humans

2. Bears

3. Raccoons

Explanation:

Heterotroph means that an organism gets energy from other things, unlike plants that produce their own food.

Hope I could help!!

7 0

3 years ago

How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!

Nuetrik [128]

Answer: The mass of solid NaOH required is 80 g

Explanation:

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

$\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}$

where,

n = acidity for bases = 1 (For NaOH)

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

$\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq$

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}$

Or,

$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$ ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

$5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g$

Hence, the mass of solid NaOH required is 80 g

4 0

4 years ago

Use the mole concept to calculate the number of atoms that are in a 1.75-mol sample of CHCl3.

Fiesta28 [93]

This is how I got to that answer. Since we don't know how many atoms there are in a mole, we use the number 6.02 x 10^-23. Now, just plug in what you have in the equation:

1.75 moles ChCl3 x (6.02 x 10 ^-23) / 1 mole = 1.0535 x 10^-22 atoms.

6 0

3 years ago

If 237.5 g of lead (II) oxide are produced in the following reaction, how many liters of oxygen are produced at STP

Dennis_Churaev [7]

It’s 11.9 liters of oxygen

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3 years ago