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OverLord2011 [107]
3 years ago
12

"what are the half lives for uranium-235 and uranium-238?"

Chemistry
1 answer:
lilavasa [31]3 years ago
7 0
Uranium-238 - 4.46 billion years
Uranium-235 - 704 million years
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The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?
Vedmedyk [2.9K]

Answer : The volume of pure diamond is 0.493inch^3

Explanation : Given,

Density of pure carbon in diamond = 3.52g/cm^3

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}

Molar mass of carbon = 12 g/mol

\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

Density=\frac{Mass}{Volume}

Now putting all the given values in this formula, we get:

3.52g/cm^3=\frac{284.4g}{Volume}

Volume = 80.8cm^3

As we know that:

1cm^3=0.061inch^3

So,

Volume = 0.061\times 80.8inch^3

Volume = 0.493inch^3

Therefore, the volume of pure diamond is 0.493inch^3

5 0
3 years ago
When the products of a reaction are hotter than the reactants: The reaction is exothermic. The reaction is endothermic. The reac
AlekseyPX
<span>Exothermic reaction evolves energy due to which products get hot...</span>
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3 years ago
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Identify the item that does not have kinetic energy.
d1i1m1o1n [39]

Answer:

D

Explanation:

there is no other answer choice that does not move. This is a fool-proof question because all the other answer choices contain movement except the butterfly resting

4 0
3 years ago
When the ocean washes farther up shore
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High tide is when the ocean rises 

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3 years ago
811.68 J of energy are used on a 95g chunk of unknown metal. Calculate the resulting temperature change if the specific heat of
Ivan

Answer:

16 °C

Explanation:

Step 1: Given data

  • Provided heat (Q): 811.68 J
  • Mass of the metal (m): 95 g
  • Specific heat capacity of the metal (c): 0.534 J/g.°C

Step 2: Calculate the temperature change (ΔT) experienced by the metal

We will use the following expression.

Q = c × m × ΔT

ΔT = Q/c × m

ΔT = 811.68 J/(0.534 J/g.°C) × 95 g = 16 °C

6 0
3 years ago
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