True or false, to convert square meters to square yards, multiply 3 by 9.29 x 10^-2

PLEASE HELP WITH THESE TWO QUESTIONSSS 1. Which value is equivalent to sin20∘?

Nata [24]

Answer:

a) $\cos(70\degree)$

b) 12.72 units

Step-by-step explanation:

Recall that the sine and cosine are completed functions.

This means that: $\sin(x)=\cos(90-x)$

$\sin(20\degree)=\cos(90-20)$

$\sin(20\degree)=\cos(70\degree)$

Recall that: sine ratio is opposite/hypotenuse

$\sin 58=\frac{|PQ|}{15}$

This implies that:

$|PQ|=15\sin 58$

$|PQ|=15(0.848)$

$|PQ|=12.72$

4 0

4 years ago

Jayesh is looking into joining a gym. He has a budget of $65 per month. The gym he wants to join has fees based on the number of

puteri [66]

Number of visits can be only a whole number, the solution should be 9 visits

8 0

3 years ago

K/13 = 0.6/0.5 what does that equal

photoshop1234 [79]

$\frac{k}{13}$ = $\frac{0.6}{0.5}$ equals k = 15.6

First, simplify $\frac{0.6}{0.5}$ to 1.2. Your problem should look like: $\frac{k}{13}$ = 1.2
Second, multiply both sides by 13. Your problem should look like: k = 15.6, which is the answer.

5 0

3 years ago

Determine which numbers the equations need to be multiplied by to form opposite terms of the y-variable. 3x - 1 4 y = 15 2 3 x -

sesenic [268]

In the elimination method, one variable is eliminated from the system of equations to find the value of the other.

To create the opposite terms of the x-variable-

The first equation be multiplied by the number 4.

Second equation be multiplied by the number -6.

<h3>What is the elimination method?</h3>

To solve the system of equations and find the value of the variables, the elimination method is used.

In this method, one variable is eliminated from the system of equations to find the value of the other.

Given information-

The system of the equation given in the problem is,

$\rm 3x-\dfrac{1}{4}y=15$

The second equation given in the problem is;

$\rm \dfrac{2}{3}x-\dfrac{1}{6}y=6$

To eliminate the x term, make the coefficient of x of both equations equal.

It can be done by multiplying the coefficient of x term of the first equation to the second equation and the coefficient of x term of the second equation to the first equation.

The first equation is multiplied by;

$\rm 4\times 3x-4\times \dfrac{1}{4}y=15\times 4\\\\12x-y=50$