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scoray [572]
3 years ago
9

Whats the answer to 1+3x=-2(x+7)

Mathematics
2 answers:
Hitman42 [59]3 years ago
6 0

Answer:

x = -3

Step-by-step explanation:

1+3x=-2(x+7)

Distribute

1+3x = -2x-14

Add 2x to each side

1+3x+2x = -2x+2x-14

1+5x = -14

Subtract 1 from each side

1-1+5x= -14-1

5x = -15

Divide each side by 5

5x/5 = -15/5

x = -3

Lyrx [107]3 years ago
4 0

Answer:

-3

Step-by-step explanation:

Please give me brainliest.

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13. Describe the number of solutions for the equation. (1 point)
Anna11 [10]

Answer:

no solution

Step-by-step explanation:

Given

3(x - 3) = 3x , that is

3x - 9 = 3x ( add 9 to both sides )

3x = 3x + 9 ( subtract 3x from both sides )

0 = 9 ← not possible

This indicates the equation has no solution

4 0
3 years ago
A function f(x)f(x) is graphed on the coordinate plane.
Effectus [21]

<u>Answer</u>

-4x - 2


<u>Explanation</u>

To get the function needed, first calculate the slope of the graph.

slope = (change in y) / (change in x)

          = (2 - -2)/(-1 - 0)

          = 4/-1

           = -4

Now use one of the point (-1, 2) in the graph and a general point (x,y) to find the function.

-4 = (y - 2)/(x - -1)

-4(x + 1) = y - 2

-4x - 4 = y - 2

y = -4x - 4 + 2

  = -4x - 2


∴ f(x) =  -4x - 2

6 0
3 years ago
9(-6+4h). Help me please
sertanlavr [38]

Answer:

-54+36h

Step-by-step explanation:

4 0
3 years ago
A taxi driver charges $3 for every kilometre driven, plus $4 per trip.
lilavasa [31]

Answer:ggg

Step-by-step explanation:ggggg

5 0
3 years ago
Read 2 more answers
4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
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