Question

Graph g(x), where f(x) = 3x − 1 and g(x) = f(x + 1).

Answer 1

Answer:

a line labeled g of x that passes through points negative 2, negative 4 and 0, 2

$\huge \mathfrak{Explanation}\\g(x)=f(x+1)=3(x+1)-1\\g(x)=3x+2$

A line y=g(x) is y=3x+2.

1)Put x=-2

$\implies g(-2)=3(-2)+2=-6+2=\color{red}{-4}$

2)Put x=0

$\implies g(0)=3(0)+2=\color{red} {2}$

Answer 2

Answer:

It's a line labeled $g(x)$ that passes through points $(-2;-4)$ and $(0;2)$,

Step-by-step explanation:

To graph $g(x)$, first we have to find that function by replacing $f(x)$.

The $g(x)$ is defined as the first function but with its variable increased by 1 unit, instead of $x$, we write $x+1$ as its variable.

$g(x)=f(x+1)=3(x+1)-1$

$g(x)=3x+3-1$

$g(x)=3x+2$

So, if we graph this function we'll have something like the image attached. It's a line labeled $g(x)$ that passes through points $(-2;-4)$ and $(0;2)$, which is showed on the graph.