C
Using Descartes' rule of signs
look for the number of sign changes in f(x)
+ / + / - / -
There is 1 sign change hence 1 positive zero
f(-x) = -x³ + x² + 8x - 8
look for the number of sign changes in f(- x)
- / + / + / -
there are 2 sign changes hence 2 possible negative zeros
Answer I think:
35,
35,
35,
35
No idea hope its helpfull
Answer:
what is the question
Step-by-step explanation:
there is no question
↪Do you have options?
↪ Are we solving for the value of "x"? if so then follow the following steps! (they are short because it isnt more to this problem)
Step 1▶6(x)+2-2(x)+2=?
? = 0
Step 2▶ 4(x) = 0
You would have to divide on your sides of the equation by the number four
▶We have discovered that it has "One Solution" ◀
So, therefore, the value of 'x' is 0 ; x = 0✔
